Ask question

Ask question

All categories

2 years ago

12

You are planning a trip to Spain in the summer of 2009. You estimate for an entire month in Spain, you will need $7,139.00 (This

includes Airfare, room and board, daily expenses, and a Eurail Pass). You save for 7 months and your monthly gross salary is $2770.22. Given that Social Security is 6.2% of your semi-monthly income, Medicare is 1.45% of your semi-monthly income, your monthly expenses are $1,200, and you pay State and Federal taxes in the amount of $52.00 and $101.00 respectively semi-monthly, how much will you have saved up and will you have saved enough to visit Spain in August? Round all your answers to the nearest cent.

1 answer:

Komok [63]2 years ago

4 0

Answer: $7,366.10; yes

Step-by-step explanation:

You might be interested in

A bacon cheeseburger at a popular fast food restaurant contains 2,070mg of sodium, which is 86% of the recommended daily amount.

svp [43]

2,070mg 86%
— = —
? mg 100%

Cross multiply (2,070 X 100) which equals 207,000

Then divide 207,000 by 86 which equals
2,406.976

Then you round so you get 2,407

The Answer is 2,407 milligrams

5 0

2 years ago

What is the sum of StartRoot negative 2 EndRoot and StartRoot negative 18 EndRoot?

Darya [45]

Answer:

$4 \sqrt{2} i$

Step-by-step explanation:

We want to find the sum of

$\sqrt{ - 2} + \sqrt{ - 18}$

We can rewrite this as

$\sqrt{ 2 \times - 1} + \sqrt{ 18 \times - 1}$

This becomes;

$\sqrt{2} \times \sqrt{ - 1} + \sqrt{18} \times \sqrt{ - 1}$

Recall that;

$i = \sqrt{ - 1}$

This implies that;

$\sqrt{2} i + 3 \sqrt{2} i$

Combine like terms:

$4 \sqrt{2} i$

3 0

1 year ago

A sailboat is sitting at rest near its dock. A rope attached to the bow of the boat is drawn in over a pulley that stands on a p

irina [24]

Answer:

The boat is approaching the dock at rate of 2.14 ft/s

Step-by-step explanation:

The situation given in the question can be modeled as a triangle, please refer to the attached diagram.

A rope attached to the bow of the boat is drawn in over a pulley that stands on a post on the end of the dock that is 5 feet higher than the bow that means x = 5 ft.

The length of rope from bow to pulley is 13 feet that means y = 13 ft.

We know that Pythagorean theorem is given by

$x^{2} + y^{2} = z^{2}$

Differentiating the above equation with respect to time yields,

$2x\frac{dx}{dt} + 2y\frac{dy}{dt} = 2z\frac{dz}{dt}$

$x\frac{dx}{dt} + y\frac{dy}{dt} = z\frac{dz}{dt}$

dx/dt = 0 since dock height doesn't change

$y\frac{dy}{dt} = z\frac{dz}{dt}$

$\frac{dy}{dt} = \frac{z}{y} \frac{dz}{dt}$

The rope is being pulled in at a rate of 2 feet per second that is dz/dt = 2 ft/s

First we need to find z

z² = (5)² + (13)²

z² = 194

z = √194

z = 13.93 ft

So,

$\frac{dy}{dt} = \frac{z}{y} \frac{dz}{dt}$

$\frac{dy}{dt} = \frac{13.93}{13}(2)$

$\frac{dy}{dt} = 2.14$ $ft/s$

Therefore, the boat is approaching the dock at rate of 2.14 ft/s

8 0

1 year ago

Suppose that the researchers wanted to estimate the mean reaction time to within 6 msec with 95% confidence. Using the sample st

Lisa [10]

Answer:

a) The 95% confidence interval would be given by (509.592;550.308)

b) n=523 rounded up to the nearest integer

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=530$ represent the sample mean for the sample

$\mu$ population mean

s=70 represent the sample standard deviation

n=48 represent the sample size (variable of interest)

Confidence =95% or 0.995

Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are df=n-1=48-1=47

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,47)".And we see that $z_{\alpha/2}=2.01$

Now we have everything in order to replace into formula (1):

$530-2.01\frac{70}{\sqrt{48}}=509.692$

$530+2.01\frac{70}{\sqrt{48}}=550.308$

So on this case the 95% confidence interval would be given by (509.592;550.308)

Part b

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

Assuming that $\hat \sigma =s$

And on this case we have that ME =6msec, and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 95% of confidence interval is provided, $z_{\alpha/2}=1.96$ , replacing into formula (b) we got:

$n=(\frac{1.96(70)}{6})^2 =522.88 \approx 523$

So the answer for this case would be n=523 rounded up to the nearest integer

3 0

1 year ago

Javier used the expression below to represent his score in a game of mini-golf.

shtirl [24]

Answer: The correct options are

(2) The coefficient is 2.

(3) The constant is 5.

(6) There are two terms.

Step-by-step explanation: Given that Javier used the expression below to represent his score in a game of mini-golf :

$E=3x+x+5-2x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

We are to select the correct statements about the parts of the simplified expression if Javier simplifies the expression.

The simplification of expression (i) is as follows :

$E\\\\=3x+x+5-2x\\\\=(3+1-2)x+5\\\\=2x+5.$

Therefore, we get

the constant term is 5,

the coefficient of x is 2

and

There are two terms.

Thus, options (2), (3) and (6) are correct.

4 0

2 years ago

Read 2 more answers