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maxonik [38]
2 years ago
8

If each jar below contains exactly one mole of each element, which jar contains the greatest mass? (The atomic mass of each elem

ent is given.)
MolesAQ2
A. The jar of carbon.
B. The jar of sulfur.
C. The jar of aluminum.
D. Each jar contains the same mass.
Chemistry
1 answer:
k0ka [10]2 years ago
4 0

B.

The jar of sulfur.

Explanation:

The molar mass of sulfur is 32 g/mol

The molar mass of Aluminium is 27g/mol

The molar mass of carbon is 12 g/mol

Therefore based on these numbers, it is evident that a mole of Sulfur weighs the heaviest.

Different elements weight different because their atoms have different mass numbers. The lower you go in the periodic table the heavier the atoms became because they have more atomic units (neutrons and protons) in their nuclei.

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The volume of a single strontium atom is 4.15×10-23 cm3. What is the volume of a strontium atom in microliters
Ivenika [448]

Answer:-  4.15*10^-^2^0\mu L

Solution:- It is a volume unit conversion problem where we are asked to convert the volume from cm^3 to microliters.

We know that:

1cm^3 = 1 mL

1mL=10^-^3L

and, 1L=10^6\mu L

Let's use these conversions factors for the desired conversion using dimensional as:

4.15*10^-^2^3cm^3(\frac{1mL}{1cm^3})(\frac{10^-^3L}{1mL})(\frac{10^6\mu L}{1L})

= 4.15*10^-^2^0\mu L

So, the answer is  4.15*10^-^2^0\mu L .

7 0
2 years ago
The statement that percent yield can never be greater than theoretical yield is another example of the ________.
Gnom [1K]
We can rephrase the statement with a little more specificity in order to understand the answer here.

The mass of the products can never be more than the The mass that is expected.
3 0
2 years ago
Dry ice is solid carbon dioxide. A 0.050-g sample of dry ice is placed in an evacuated 4.6-L vessel at 30 °C. Calculate the pres
goldenfox [79]

The answer is 6.1*10^-3 atm.

The pictures and explanations are there.

3 0
2 years ago
If honey has a density of 1.36 g/ml what is the mass of 1.25 qt reported in kilograms
yawa3891 [41]
Answer;
1.6 kg.

Solution;
 
The density is 1.36 g/ml;

The volume is 1.25 qt
However; 1 qt = 946.35 ml 

Mass is given by; density × volume;
    = 1.25 qts × 946.25 ml/qt × 1.36 g/ml =1609 g 
but; 1 kg = 1000 g
Hence the mass = 1609/1000 = 1.609 Kg or 1.61 (sig figs)

7 0
2 years ago
In a particular mass of kau(cn)2, there are 6.66 × 1020 atoms of gold. What is the total number of atoms in this sample?
Vinvika [58]

Total number of atoms in the sample is the sum of number of atoms of all the elements present in the sample.

Number of gold, Au atoms in KAu(CN)_2 = 6.66\times 10^{20} atoms     (given)

From the formula of compound that is KAu(CN)_2 it is clear that the number of potassium and gold are same whereas those of carbon and nitrogen are 2 times of them.

So, the number of atoms of each element is:

Number of potassium, K atoms in KAu(CN)_2 = 6.66\times 10^{20} atoms    

Number of carbon, C atoms in KAu(CN)_2 = 2\times6.66\times 10^{20} atoms = 13.32\times 10^{20}

Number of nitrogen, N atoms in KAu(CN)_2 = 2\times6.66\times 10^{20} atoms = 13.32\times 10^{20}

Total number of atoms in KAu(CN)_2 = Number of gold, Au atoms+Number of potassium, K atoms +Number of carbon, C atoms + Number of nitrogen, N atoms

Total number of atoms in KAu(CN)_2 = 6.66\times 10^{20}+6.66\times 10^{20}+13.32\times 10^{20}+13.32\times 10^{20}

Total number of atoms in KAu(CN)_2 = 39.96\times 10^{20} atoms

Hence, the total number of atoms in KAu(CN)_2 is 3.996\times 10^{21} atoms.

7 0
2 years ago
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