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Kamila [148]
2 years ago
11

Why is radioactive dating important when approximating the age of earth?

Chemistry
2 answers:
Lisa [10]2 years ago
7 0

Answer:

The radioactive dating method is one of the efficiently used methods in order to calculate the age of the rocks, meteorites, fossils and various other objects, depending upon the rate at which radioactive isotopes decay. In this method, an unstable element changes into a stable one, releasing some amount of radiation and losing a certain amount of energy.

This is efficient in determining the age of the earth. The earth is comprised of rocks that are present from the time of its formation. These rocks can be dated using this method and the approximate age of the rock is evaluated.

The Uranium-Lead dating (²³⁸U-²⁰⁶Pb) method was used to date the smaller zircon crystals of Australia that are about 4.4 billion years old. The half-life of U-238 is approximately 4.5 billion years, which shows that these are one of the oldest rocks on earth and helps in understanding how old the earth is.

Half-life is defined as the time required by a radioactive isotope to decay half of its atoms.

So the radioactive dating method is one of the common method gives the approximate age of the earth.

Furkat [3]2 years ago
6 0

Answer:

So, we rely on radiometric dating to calculate their ages. Radiometric dating, or radioactive dating as it is sometimes called, is a method used to date rocks and other objects based on the known decay rate of radioactive isotopes.

Explanation:

radiometric dating is a very accurate way to date the Earth.We know it is accurate because radiometric dating is based on the radioactive decay of unstable isotopes. When an unstable Uranium (U) isotope decays, it turns into an isotope of the element Lead (Pb).

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2.1. The lithium ion in a 250,00 mL sample of mineral water was
juin [17]

Answer:

11482 ppt of Li

Explanation:

The lithium is extracted by precipitation with B(C₆H₄)₄. That means moles of Lithium = Moles B(C₆H₄)₄. Now, 1 mole of B(C₆H₄)₄ produce the liberation of 4 moles of EDTA. The reaction of EDTA with Mg²⁺ is 1:1. Thus, mass of lithium ion is:

<em>Moles Mg²⁺:</em>

0.02964L * (0.05581mol / L) = 0.00165 moles Mg²⁺ = moles EDTA

<em>Moles B(C₆H₄)₄ = Moles Lithium:</em>

0.00165 moles EDTA * (1mol B(C₆H₄)₄ / 4mol EDTA) = 4.1355x10⁻⁴ mol B(C₆H₄)₄ = Moles Lithium

That means mass of lithium is (Molar mass Li=6.941g/mol):

4.1355x10⁻⁴ moles Lithium * (6.941g/mol) = 0.00287g. In μg:

0.00287g * (1000000μg / g) = 2870μg of Li

As ppt is μg of solute / Liter of solution, ppt of the solution is:

2870μg of Li / 0.250L =

<h3>11482 ppt of Li</h3>

4 0
2 years ago
`suppose you were tasked with producing some nitrogen monoxide (a.k.a. nitric oxide). i'm sure this is often requested of you. y
Umnica [9.8K]
N(H₂O):n(NO)=6:4(3:2), n(NO)=2·3,5mol÷3=2,33mol
So it is a).
7 0
2 years ago
Read 2 more answers
Based on the values you obtained for δh∘rxn, which of the reactions would you expect to be thermodynamically favorable and which
QveST [7]
Following reactions are involved in present reaction
1) A<span>g+(aq)   +    Li(s)     →       Ag(s)     +       Li+(aq)      </span><span>−      384.4kJ
2) </span><span>2Fe(s)     +     2Na+(aq)      →        Fe2+(aq)      +       2Na(s)     +   392.3kJ
</span>3)  <span>2K(s)     +      2H2O(l)      →      2KOH(aq)       +H2(g)       −393.1kJ

In above reaction, reaction 1 and 3 has negative value of </span>δh∘f, while reaction 2 has posiyive value of <span>δh∘f. As per the sign convention positive sign indicates that heat is given out during the reaction, while negative sign indicates heat is to be supplied for reaction to occur. In alternative words, product formed in reaction 2 is stable as compared to reactant. Hence, it is thermodynamically favorable. </span>
7 0
2 years ago
What is the net ionic equation for 2Sb(OH)3 (s) + 3Na2S (aq) = Sb2S3 + 6NaOH
tatuchka [14]

Answer:

2Sb^(+3) (aq) + 3S^(-2) (aq) = Sb_2•S_3

Explanation:

First of all, let us balance the equation to give;

2Sb(OH)3 (s) + 3Na2S (aq) = Sb2S3 + 3NaOH

Now, we can observe the presence of positive Sodium ions (Na+) and negative hydroxyl ions (OH-) on both left and right sides of the equation.

Now, the two ions will cancel out. These ions are not really involved in the overall reaction and thus do not require being written in the overall equation. Hence, the overall net ionic reaction can now be written as:

2Sb^(+3) (aq) + 3S^(-2) (aq) = Sb_2•S_3

6 0
2 years ago
SnO2 is reduced by carbon according to this reaction: SnO2 + C ???? Sn + CO2. How many liters of CO2 are produced if 300.0 grams
andrew-mc [135]

Explanation:

The given reaction is as follows.

         SnO_{2} + C \rightarrow Sn + O_{2}

a).   Molar mass of SnO_{2} is [(mass of Sn) + (2 × mass of O)].

Therefore, molar mass of SnO_{2} = (118.7 + 2 × 16) g/mol = 150.7 g/mol

Since, it is known that number of moles equal mass divided by molar mass. So, moles of Sn will be calculated as follows.

               No. of moles = \frac{mass}{molar mass of SnO_{2}}

                                      = \frac{300 g}{150.7 g/mol}

                                      = 2.53 mol

As it is given that 1 mole of SnO_{2} produces 1 moles of Sn and 1 moles of CO_{2}. Hence, 2.53 moles of SnO_{2} will also produce 2.53 moles of Sn and 2.53 moles of CO_{2}.

Volume of 1 mole of CO_{2} at STP is 22.4 L. Therefore, volume of 2.53 moles of CO_{2} will be calculated as follows.

                  2.53 × 22.5 L = 56.67 L

Hence, 56.67 L of CO_{2} are produced if 300.0 grams of tin are produced at STP.

b).  Mass of tin is given as 1800.0 g. So, number of moles will be calculated as follows.

               No. of moles = \frac{mass}{molar mass of tin}

                                      = \frac{1800.0 g}{118.7 g/mol}

                                      = 15.2 moles

As 15.2 moles of SnO_{2} produces 15.2 moles of Sn. Therefore, weight of SnO_{2} will be calculated as follows.

                   Mass = no. of moles × molar mass of SnO_{2}

                             = 15.2 moles × 150.7 g/mol

                             = 2290.64 g

Hence, 2290.64 grams of SnO_{2} are required to produce 1800.0 grams of tin.

c).   Mass of carbon given is 100.0 grams.

             No. of moles = \frac{mass}{molar mass of carbon}

                                    = \frac{100 g}{12 g/mol}

                                      = 8.33 moles

As, 1 mole of carbon is produced by 1 mole of tin. So, 8.33 mole of carbon will be produced by 8.33 moles of tin.

Therefore, calculate mass of tin produced as follows.

                        Mass = no. of moles × molar mass of Sn

                             = 8.33 moles × 118.7 g/mol

                             = 988.8 g

Hence, 988.8 grams of tin will be produced per 100 grams of carbon used.

8 0
2 years ago
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