How many grams of nano3 are needed to prepare 100 grams of a 15.0 % by mass nano3 solution? will give brainliest
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Answer:-
Solution:- It is a volume unit conversion problem where we are asked to convert the volume from to microliters.
We know that:
= 1 mL
and,
Let's use these conversions factors for the desired conversion using dimensional as:
=
So, the answer is .
0.6137 g of KHP contains 1.086 × 10^21 acidic protons.
Number of moles of KHP = mass of KHP/molar mass of KHP
Molar mass of KHP = 204.22 g/mol
Mass of KHP = 0.6137 g
Number of moles of KHP = 0.6137 g/204.22 g/mol = 0.003 moles of KHP
Now, 1 each molecule of KHP contains 1 acidic proton.
For 0.003 moles of KHP there are; 0.003 × 1 × NA
Where NA is Avogadro's number.
So; 0.003 moles of KHP contains 0.003 × 1 × 6.02 × 10^23
= 1.086 × 10^21 acidic protons.
Learn more: brainly.com/question/16672114
