Describe the key features of the parabola y2 = 8x.
2 answers:
I just did this question, here's the my answer and the sample answer it gave. (:
Sample Response: The value of p is 2. The parabola opens to the right. The focus is at (2, 0) and the equation of the directrix is x = –2. The axis of symmetry is y = 0. The vertex is at the origin, (0, 0).
I hope that helps a little!
Sample Response: The value of p is 2. The parabola opens to the right. The focus is at (2, 0) and the equation of the directrix is x = –2. The axis of symmetry is y = 0. The vertex is at the origin, (0, 0).
I hope that helps a little!
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Answer:
The value of the parameter is λ is 0.03692
Step-by-step explanation:
Consider the provided function.
for −∞ < x < ∞.
It is given that standard deviation is given as 38.3 km.
Now we need to calculate the value of parameter λ.
The general formula for the probability density function of the double exponential distribution is:
Where μ is the location parameter and β is the scale parameter.
Compare the provided equation with the above formula we get.
and μ = 0.
Standard deviation = √2β
Now substitute the value of β in .
Hence, the value of the parameter is λ is 0.03692