Question

A theater group made appearances in two cities. The hotel charge before tax is the second city was $ 1000 higher than in the first. The tax in the first city was 8.5 % and the tax in the second city was 5.5 %. The total hotel tax paid for the two cities was $ 790 . How much was the hotel charge in each city before tax?

Answer 1

Answer:

First city was= $ x = $ 5604

Second city was =$(x +1000) = $6604

Explanation:

The tax in the first city was 8.5%

The tax in the second city was 5.5%

Let the hotel charge amount before tax for the first city be $x

Let the hotel charge amount before tax for the second city be: $(x+1000)

Applying the tax

First city will be;

8.5/100*(x) = $0.085 x

Second city will be;

5.5/100* (x+100) =0.055(x+100) = $ (0.055x+5.5)

Total hotel tax paid for the two cities was ;

0.085 x + 0.055 x + 5.5 = $(0.14 x + 5.5)

This expression for total hotel tax paid for the two cities is equal to $790

$(0.14 x + 5.5) = $ 790

0.14 x = 790 -5.5

0.14 x = 784.5

x= 784.5/0.14

x=5603.57

x= $5604 ( nearest $)

Before tax, hotel charge for;

First city was= $ x = $ 5604

Second city was =$(x +1000) = $6604