Answer:
The answer to your question is below
Step-by-step explanation:
Data
Equation 25x² + 64y² = 1600
Process
1.- Divide all the equation by 1600
25x²/1600 + 64y²/ 1600 = 1600/1600
-Simplify
x²/64 + y²/ 25 = 1
2.- Equation of a horizontal ellipse
3.- Find a, b and c
a² = 64 a = 8
b² = 25 b = 5
-Calculate c with the Pythagorean theorem
a² = b² + c²
-Solve for c
c² = a² - b²
-Substitution
c² = 8² - 5²
-Simplification
c² = 64 - 25
c² = 39
-Result
c = √13
4.- Find the center
C = (0, 0)
5.- Find the vertices
V1 = (-8, 0) V2 = (8, 0)
6.- Find the foci
F1 = (-√13, 0) F2 = (√13, 0)
To arrive at the answer, I graphed the piecewise function using a graphing calculator, then evaluated it at x=38 and x=52. I drew a line at y=445 and found the point of intersection on the graph.
a) The difference between earnings for 52 hours ($580) and earnings for 38 hours ($380) is
$200.
b) An employee must work
43 hours to earn $445.
<span>1)Given: AB = 4 AD = 6
What is the name of the radius of the larger circle?
the answer part 1) is
the radius </span>of the larger circle is AD
<span>2)Given: AB = 4 AD = 6
What point is in the interior of both circles?
the answer Part 2) is
The point A (the center of the circles)
</span><span>3) Given: AB = 4 AD = 6
Which points are in the exterior of both circles?</span><span>
the answer Part 3) is
</span><span>E and G
</span><span>4)The circles are _____.
</span><span>the answer Part 4) is
</span><span>concentric
</span>
<span>5)If AC = 20 and BD = 8, what is the radius of the smaller circle?
</span>we know that
radius smaller circle=AB
and
AB=AC-BD--------> AC=20-12-------> AC=8 units
the answer part 5) is
the radius of the smaller circle is 12 units
<span>6)Given: AB = 4 AD= 6
What is the length of BD?</span>
we know that
AD=AB+BD
solve for BD
BD=AD-AB--------> BD=6-4-----> BD=2 units
the answer Part 6) is
the length of BD is 2
<span>7)Given: AB = 4 AD = 6
What is the name of the radius of the smaller circle?</span>
the answer Part 7) is
the name of the radius of the smaller circle is AB
146 minutes in total. One student =3 minutes. So then 42x3= 126. Class picture is 10x2=20. So then add both of them you get 146.
