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arsen [322]
2 years ago
5

tions - Part 1 A relation is plotted as a linear function on the coordinate plane starting at point E (0, 27)(0, 27) and ending

at point F (5,−8)(5,−8) . What is the rate of change for the linear function and what is its initial value? Select from the drop-down menus to correctly complete the statements. The rate of change for the linear function is and the initial value is
Mathematics
2 answers:
frutty [35]2 years ago
7 0

Answer:

The initial value is -7 and the rate of change is 27

Step-by-step explanation:


stealth61 [152]2 years ago
4 0
We are given with
<span>E (0, 27)
</span><span>F (5,−8)

and we are asked to get the rate of change and the initial value:

To get the rate of change, we simply have to use the slope formula:
m = (-8 - 27) / (5 - 0) = -7
The rate of change is -7

The initial value is the value of y when x is 0 which is the coordinates of E. So, the initial value is 27.</span>
You might be interested in
A game is played using one die. If the die is rolled and shows 1, the player wins $5. If the die shows any number other than 1,
mash [69]

Answer:

1/5

Step-by-step explanation:

i had a similar question

For each roll you start with paying 2 dollars and you only with 10 dollars one out of 6 rolls (on average). 

So the cost for one play is 2 dollars and your win is 10/6. 

Value is -2+10/6=-1/3 dollars

So you lose 1/3 dollars on average with each game

since you have no limited rolls u put 1/5

this from another question but both same just different numbers

6 0
2 years ago
A baseball player has 39 hits in 134 times at bat. how many hits must he get in the next 46 times at bat to finish the year with
faust18 [17]

Answer:

He must get 33 hits in his next 46 times at bat to finish the year with a .400 batting average

Step-by-step explanation:

The player has already batted 134 times and will still bat 46 times. So in the end of the year, he is going to have 134 + 46 = 180 at bats.

How many hits does he need to have to hit .400?

This is 40% of 180, which is 0.4*180 = 72.

He has already 39 hits, so in his next 46 at bats, he will need 72 - 39 = 33 hits.

4 0
2 years ago
Jones of Boston borrowed $40,000, on a 90-day 10% note. After 60 days, Jones made an initial payment of $6,000. On day 80, Jones
MaRussiya [10]

Answer:

$34,666.67

Step-by-step explanation:

Step 1: Calculate the interest for 60 days.

(40000*60/360 )* 0.10 = $666.67

Step 2: Amount = Principal + Interest = $40,000 + 666.67 = $40,666.67

Step 3 : After 60 days, he paid $6000.

Remaining balance of the first payment = 40666.67 - 6000 = $34,666.67

Thank you.

8 0
1 year ago
A savings and loan association needs information concerning the checking account balances of its local customers. A random sampl
Citrus2011 [14]

Answer:

a) 98% confidence interval for the true mean checking account balance for local customers.

(453.586 , 874.693)

b)   95% confidence interval for the standard deviation.

(214.91 , 441.53)

Step-by-step explanation:

Given a size of sample 'n' =14

given mean of the sample x⁻ = $664.14

standard deviation of the sample 'S' = $297.29.

a)

<u>98% of confidence intervals</u>

<u></u>(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } , x^{-}+ t_{\alpha }\frac{S}{\sqrt{n} } )<u></u>

The degrees of freedom γ=n-1 =14-1 =13

t₁₃ = 2.650 at 98% of confidence level of signification.

(664.14- 2.650\frac{297.29}{\sqrt{14} } , 664.14+ 2.650\frac{297.29}{\sqrt{14} } )

on calculation, we get

(664.14-210.553 , 664.14+210.553)

(453.586 , 874.693)

98% confidence interval for the true mean checking account balance for local customers.

(453.586 , 874.693)

<u>95% of confidence intervals</u>

({s\sqrt{\frac{n-1}{X^{2} _{(\frac{\alpha }{2} ,n-1) } } } ,s\sqrt{\frac{n-1}{X^2_{\frac{1-\alpha }{2},n-1 } } }  )

The degrees of freedom γ=n-1 =14-1 =13

X^2_{0.05,13} =22.36     (check table)

X^2_{0.95,13} = 5.892    (check table)

(297.29. (\sqrt{\frac{14-1}{X^2_{0.05,13}  } } ),297.29(\sqrt{\frac{14-1}{X^2_{0.95,13} } } )

(297.29. (\sqrt{\frac{14-1}{22.36  } } ),297.29(\sqrt{\frac{14-1}{5.892 } } )

(214.91 , 441.53)

95% confidence interval for the standard deviation.

(214.91 , 441.53)

7 0
2 years ago
A six foot man is standing 10 feet away from a 20 foot lamppost. what is the length of his shadow?
elena55 [62]
There are two congruent triangles that are being formed from the lamppost, the light, the ground and the man. Always try to draw a picture for these types of problems. It helps a lot when solving. Your answer should be about 4.3ft

4 0
1 year ago
Read 2 more answers
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