Answer:
20 by 20
Step-by-step explanation:
the new dimensions have to be 12 because 12×12 =144 so you would add 8 to 12 and get 20 for each side
Answer:
The population that gives the maximum sustainable yield is 45000 swordfishes.
The maximum sustainable yield is 202500 swordfishes.
Step-by-step explanation:
Let be
, the maximum sustainable yield can be found by using first and second derivatives of the given function: (First and Second Derivative Tests)
First Derivative Test

Let equalize the resulting expression to zero and solve afterwards:


Second Derivative Test

This means that result on previous part leads to an absolute maximum.
The population that gives the maximum sustainable yield is 45000 swordfishes.
The maximum sustainable yield is:


The maximum sustainable yield is 202500 swordfishes.
B. because it is 10 being subtracted from the fraction.
Answer:
Here we have given two catogaries as degree holder and non degree holder.
So here we have to test the hypothesis that,
H0 : p1 = p2 Vs H1 : p1 not= p2
where p1 is population proportion of degree holder.
p2 is population proportion of non degree holder.
Assume alpha = level of significance = 5% = 0.05
The test is two tailed.
Here test statistic follows standard normal distribution.
The test statistic is,
Z = (p1^ - p2^) / SE
where SE = sqrt[(p^*q^)/n1 + (p^*q^)/n2]
p1^ = x1/n1
p2^ = x2/n2
p^ = (x1+x2) / (n1+n2)
This we can done in TI_83 calculator.
steps :
STAT --> TESTS --> 6:2-PropZTest --> ENTER --> Input all the values --> select alternative "not= P2" --> ENTER --> Calculate --> ENTER
Test statistic Z = 1.60
P-value = 0.1090
P-value > alpha
Fail to reject H0 or accept H0 at 5% level of significance.
Conclusion : There is not sufficient evidence to say that the percent of correct answers is significantly different between degree holders and non-degree holders.
After 20 minutes Clint is on page = 151
After 45 minutes Clint is on page = 181
Time slot =
minutes
Difference in pages in 25 minutes =
pages.
Lets suppose Clint is reading each page at same pace.
So , In 25 minutes, he can read = 30 pages
In 1 minute he can read =
pages
Initial time is 20 minutes, so he can read the number of pages in 20 minutes = 
So, number of pages Clint read prior to study hall were =
pages.