Question

An unopened cereal box contains ‘15/28' cubic foot of cereal. If the box is full, and the length and the height of the box are ‘5/7' and ‘1(1)/(2)' feet, respectively, what is the width of the box?

Answer 1

Answer:

Width:  $\frac{1}{2}$ feet.

Step-by-step explanation:

We have been given that an unopened cereal box contains ‘15/28' cubic foot of cereal. If the box is full, and the length and the height of the box are 5/7 and 1 1/2 feet, respectively. We are asked to find the width of the box.

We know that box is in form of cuboid. We also know that volume of cuboid is product of length, width and height.

$\text{Volume}=\text{Length}\times \text{Width}\times \text{Height}$

Upon substituting our given values in above formula, we will get:

$\frac{15}{28}\text{ ft}^3=\frac{5}{7}\text{ ft}\times 1\frac{1}{2}\text{ ft}\times \text{Width}$  

$\frac{15}{28}\text{ ft}^3=\frac{5}{7}\text{ ft}\times \frac{3}{2}\text{ ft}\times \text{Width}$

$\frac{15}{28}\text{ ft}^3=\frac{15}{14}\text{ ft}^2\times \text{Width}$

$\frac{15}{28}\text{ ft}=\frac{15}{14}\times \text{Width}$

$\frac{15}{28}\times\frac{14}{15}\text{ ft}=\frac{15}{14}\times\frac{14}{15}\times \text{Width}$

$\frac{1}{2}\times\frac{1}{1}\text{ ft}=\text{Width}$

$\frac{1}{2}\text{ ft}=\text{Width}$

Therefore, the width of box is $\frac{1}{2}$ feet.