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stira [4]
2 years ago
14

The table shows data from a survey about the amount of time students spend doing homework each week. The students were either in

college or in high school:
High Low Q1 Q3 IQR Median Mean σ
College 20 6 8 18 10 14 13.3 5.2
High School 20 3 5.5 16 10.5 11 11 5.4

1. Which of the choices below best describes how to measure the spread of this data? (See picture)

2.Which of the choices below best describes how to measure the spread of this data?
Both spreads are best described with the IQR.

Both spreads are best described with the standard deviation.

The college spread is best described by the IQR. The high school spread is best described by the standard deviation.

The college spread is best described by the standard deviation. The high school spread is best described by the IQR.

Mathematics
2 answers:
satela [25.4K]2 years ago
5 0

Answer:

The correct option is: The college spread is best described by the standard deviation. The high school spread is best described by the IQR.

Step-by-step explanation:

We have given a table. According to that table  a survey about the amount of time students spend doing homework each week has been conducted. The students were either in college or in high school. Now which of the choices below best describes how to measure the spread of this data.

The correct option is: The college spread is best described by the standard deviation. The high school spread is best described by the IQR.

inessss [21]2 years ago
4 0

Answer:

the answer is actually B

Step-by-step explanation:

when drawn as a box and scatter plot, both appear to be closely symmetrical. as we know, standard deviation is used for symmetrical data, and the IQR is used for data that is not symmetrical.

i am unable to attach the box plots, but try drawing it out!

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The figure shows a square floor plan with a smaller square area that will accommodate a combination fountain and pool.The floor
dem82 [27]

Answer:

  (x, y) = (7, 4) meters

Step-by-step explanation:

The area of the floor without the removal is x^2, so with the smaller square removed, it is x^2 -y^2.

The perimeter of the floor is the sum of all side lengths, so is 4x +2y.

The given dimensions tell us ...

  x^2 -y^2 = 33

  4x +2y = 36

From the latter equation, we can write an expression for y:

  y = 18 -2x

Substituting this into the first equation gives ...

  x^2 -(18 -2x)^2 = 33

  x^2 -(324 -72x +4x^2) = 33

  3x^2 -72x + 357 = 0 . . . . write in standard form

  3(x -7)(x -17) = 0 . . . . . factor

Solutions to this equation are x=7 and x=17. However, for y > 0, we must have x < 9.

  y = 18 -2(7) = 4

The floor dimension x is 7 meters; the inset dimension y is 4 meters.

8 0
2 years ago
A pipe of diameter 64mm discharges water at a rate of 2.05mm/s into an empty cylindrical tank of diameter 7.6cm and height 2.3m.
inessss [21]

Answer:

Diameter of pipe = D = 64mm

cross sectional Area of pipe= A = pi * (D/2)^2 = pi * (32)^2 = 1024pi  mm^2

Discharge Rate of water = v = 2.05 mm/s

Volume of Cylinder = V = pi * (D/2)^2 * h = pi * (38)^2 * 2300 = 3321200pi  mm^3

(Area of pipe)*(Rate) = (Volume) / (Time)

Time = T = (Volume) / [(Area of pipe)*(Rate)]

              = (3321200pi)/(1024pi * 2.05)

              = 1582.126524s

4 0
2 years ago
Given: △PTC
Natalka [10]
Given the the two angles find the missing angle of P which is 30 degrees.

Since angle P and C are identical their sides are congruent.

The hypotenuse, the largest side is PC because it corresponds to angle T

Using Pythagorean Theorem
a^2 + b^2 = c^2

(PT)^2 + (CT)^2 = (PC)^2
Given that PT is 4 and knowing PT and CT are congruent we can rewrite this
(4)^2 + (4)^2 = (PC)^2
PC = rad(32)

Someone fact check plz
6 0
2 years ago
Read 2 more answers
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Nitella [24]

Answer:given below

Step-by-step explanation:

sqrt x^2 +81= x + 10

x^2 + 81 = (x+10)^2

x^2 + 81 = x^2 + 20x + 100

so answer is:  

x^2 + 81 = x^2 +20x + 100

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