Answer:
80 minutes or 1 h 20 minutes
Step-by-step explanation:
15-13=2
2/0.025=80
So we can conclude that it takes 80 minutes till it reaches 13 feet.
Answer:
(a) After 5 years what will be his age?
"5 + y" years old
(b) What was his age 6 years back?
"y - 6" years old
(c) His grandfather‘s age is 5 times his age, What is the age of grandfather?
"5y" years old
(d) His father’s age is 6 years more than 3 times his age. What is his father’s age?
"6 + 3y" years old
Note: Ignore the quotation marks, ""
Answer:
Step-by-step explanation:
A). An investment account earns 2.8% simple interest.
Since investment amount increases every year linearly, therefore, the modeled situation represents a LINEAR FUNCTION.
B). The price of a stock varies by 2.8% each week.
Since price of the stock may increase or decrease every week, therefore, this situation can't be modeled by any function.
Therefore, the answer is NEITHER.
C). An investment account earns 2.8% compound interest, compounded monthly.
Formula to get the value of the final amount in the account is,
Final value = Initial value × 
Here 't' = Duration of investment
It's an EXPONENTIAL FUNCTION.
Given : tan 235 = 2 tan 20 + tan 215
To Find : prove that
Solution:
tan 235 = 2 tan 20 + tan 215
Tan x = Tan (180 + x)
tan 235 = tan ( 180 + 55) = tan55
tan 215 = tan (180 + 35) = tan 35
=> tan 55 = 2tan 20 + tan 35
55 = 20 + 35
=> 20 = 55 - 35
taking Tan both sides
=> Tan 20 = Tan ( 55 - 35)
=> Tan 20 = (Tan55 - Tan35) /(1 + Tan55 . Tan35)
Tan35 = Cot55 = 1/tan55 => Tan55 . Tan35 =1
=> Tan 20 = (Tan 55 - Tan 35) /(1 + 1)
=> Tan 20 = (Tan 55 - Tan 35) /2
=> 2 Tan 20 = Tan 55 - Tan 35
=> 2 Tan 20 + Tan 35 = Tan 55
=> tan 55 = 2tan 20 + tan 35
=> tan 235 = 2tan 20 + tan 215
QED
Hence Proved
Answer:
A) ∃y(¬P(y))
B) ∀y(P(y) ^ Q(y))
C) ∀y(P(y) ^ Q(y))
D) ¬∃y(P(y) ^ Q(y))
E) ∃y(¬P(y) ^ Q(y))
Step-by-step explanation:
We will use the following symbols to answer the question;
∀ means for all
∃ means there exists
¬ means "not"
^ means "and"
A) Something(y) is not in the correct place is represented by;
∃y(¬P(y))
B) For All tools are in the correct place and are in excellent condition, let all tools in the correct place be P(y) and let all tools in excellent condition be Q(y).
Thus, we have;
∀y(P(y) ^ Q(y))
C) Similar to B above;
∀y(P(y) ^ Q(y))
D) For Nothing is in the correct place and is in excellent condition:
It can be expressed as;
¬∃y(P(y) ^ Q(y))
E) For One of your tools is not in the correct place, but it is in excellent condition:
It can be expressed as;
∃y(¬P(y) ^ Q(y))
