Jayden and Caden share a reward of 140 in a ratio of 2: 5. What fraction of the total reward does Jaden get?

Three litres of milk cost r29,95 at shop a and two liters of milk cost r15,95 at shop

Savatey [412]

At first shop the 3 liters of milk cost 2995
cost per liter = cost / volume
cost per liter = 2995 / 3 L
cost per liter = 998 per liter of milk

at second shop the two liters of milk cost 1595
cost per liter = cost / volume
cost per liter = 1595 / 2 L
cost per liter = 797.5 per liter of milk

6 0

2 years ago

Is 7.2 bigger than 7.21

Paraphin [41]

Answer:

yes

Step-by-step explanation:

4 0

2 years ago

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Gibbs Baby Food Company wishes to compare the weight gain of infants using its brand versus its competitor’s. A sample of 40 bab

Leviafan [203]

Answer:

$z=\frac{(7.6-8.1)-0}{\sqrt{\frac{2.3^2}{40}+\frac{2.9^2}{55}}}}=-0.936$

The p value can be founded with this formula:

$p_v =P(z$

Since the p value is higher than the significance level provided of 0.05 we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true mean for the Gibbs brand is significantly lower than the true mean for the competitor

Step-by-step explanation:

Information given

$\bar X_{1}=7.6$ represent the mean for Gibbs products

$\bar X_{2}=8.1$ represent the mean for the competitor

$\sigma_{1}=2.3$ represent the population standard deviation for Gibbs

$\sigma_{2}=2.9$ represent the sample standard deviation for the competitor

$n_{1}=40$ sample size for the group Gibbs

$n_{2}=55$ sample size for the group competitor

$\alpha=0.05$ Significance level provided

z would represent the statistic

Hypothesis to verify

We want to check if babies using the Gibbs brand gained less weight, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}=0$

Alternative hypothesis: $\mu_{1} - \mu_{2}< 0$

The statistic would be given by:

$z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

Replacing the info given we got:

$z=\frac{(7.6-8.1)-0}{\sqrt{\frac{2.3^2}{40}+\frac{2.9^2}{55}}}}=-0.936$

The p value can be founded with this formula:

$p_v =P(z$

Since the p value is higher than the significance level provided of 0.05 we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true mean for the Gibbs brand is significantly lower than the true mean for the competitor

5 0

2 years ago

Which is the graph of the function f(x) = x2 + 2x + 3? On a coordinate plane, a parabola opens up. It goes through (negative 2,

dmitriy555 [2]

Answer:

A

Step-by-step explanation:

6 0

1 year ago

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The greatest common divisor of two positive integers less than $100$ is equal to $3$. Their least common multiple is twelve time

tangare [24]

Answer:

129

Step-by-step explanation:

Let a and b be two numbers.

We have been given that the greatest common divisor of two positive integers less than 100 is equal to 3. We can represent this information as $GCD(a,b)=3$ .

Their least common multiple is twelve times one of the integers. We can represent this information as $LCM(a,b)=12a$ .

Now, we will use property $GCD(x,y)*LCM(x,y)=xy$ .

Upon substituting our given values, we will get:

$3*12a=ab$

$36a=ab$

Switch sides:

$ab=36a$

$\frac{ab}{a}=\frac{36a}{a}$

$b=36$

Now, we need to find a number less than 100, which is co-prime with 12 after dividing by 3.

The greatest multiple of 3 less than 100 is 99, but it is not co-prime with 12 after dividing by 3.

Similarly 96 is also not co-prime with 12 after dividing by 3.

We know that greatest multiple of 3 (less than 100), which is co-prime with 12, is 93.

Let us add 36 and 93 to find the largest possible sum of the required two integers as:

$36+93=129$

Therefore, the required largest possible sum of the two integers is 129.

3 0

2 years ago