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krok68 [10]
2 years ago
14

The area of a square can be represented by the expression x10 Which monomial represents a side of the square?

Mathematics
2 answers:
prohojiy [21]2 years ago
9 0

Answer:

x^5

Step-by-step explanation:

area \: of \: squre \:  =  {side}^{2}  \\  {x}^{10} =  {side}^{2}  \\  ({x}^{5} )^{2} =  {side}^{2}   \\ side \:  =  {x}^{5}

Hence, x^5 represents the side of the square.

melisa1 [442]2 years ago
8 0

Area\: of \: square=side^2\\x^{10}=side^2\\side=\sqrt{x^{10}}\\side=\sqrt{x^2 \times x^2 \times x^2 \times x^2 \times x^2}\\side=x \times x \times x \times x \times x\\side=x^5

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Giuseppe is studying shark attacks around the world and finds that most such attacks occur during the day. He concludes that sha
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C) not justified, since people usually swim in the ocean during the day.

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What types of concurrent constructions are needed to find the orthocenter of a triangle? A. intersection of the lines drawn perp
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Juan runs a company that makes pens. He notices that 1 out of every 9 pens are faulty. He uses a standard deck of cards to model
sergey [27]

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Isabella pitches for her high school softball team. Of the 7 pitches she throws, 5 are strikes. She uses a standard deck of cards to model her pitches, with hearts, clubs, and spades representing strikes. Which statement about her model is true?

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Suppose that 20% of the adult women in the United States dye or highlight their hair. We would like to know the probability that
Rasek [7]

Answer:

71.08% probability that pˆ takes a value between 0.17 and 0.23.

Step-by-step explanation:

We use the binomial approxiation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

p = 0.2, n = 200. So

\mu = E(X) = np = 200*0.2 = 40

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{200*0.2*0.8} = 5.66

In other words, find probability that pˆ takes a value between 0.17 and 0.23.

This probability is the pvalue of Z when X = 200*0.23 = 46 subtracted by the pvalue of Z when X = 200*0.17 = 34. So

X = 46

Z = \frac{X - \mu}{\sigma}

Z = \frac{46 - 40}{5.66}

Z = 1.06

Z = 1.06 has a pvalue of 0.8554

X = 34

Z = \frac{X - \mu}{\sigma}

Z = \frac{34 - 40}{5.66}

Z = -1.06

Z = -1.06 has a pvalue of 0.1446

0.8554 - 0.1446 = 0.7108

71.08% probability that pˆ takes a value between 0.17 and 0.23.

6 0
2 years ago
1+4=5, 2+5=12, 3+6=21,8+11=
klemol [59]
The answer is 40 because once you have 21 your just adding 19 and then that makes it 40.
8 0
2 years ago
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