All categories

2 years ago

The following graph represents dog-grooming prices at “Clean Your Paws” dog salon.

Mathematics

2 answers:

sineoko [7]2 years ago

8 0

Answer:

The answer is A) $105

Step-by-step explanation:

For this real-world problem, the cost to groom both dogs is (the puppy) + (the adult dog) = x.

For the first step, y = 40, if x <= 25.

y = 50, if 25 < x < 50.

if x >= 50, then y = 0.50x + 25

So therefore, substitute the puppy + adult dog = x

25 + 80 = x

105 = x

So, the final answer is $105.

It's on Edgen

Goryan [66]2 years ago

5 0

Answer:

$105

Step-by-step explanation:

I took the test

You might be interested in

A circular arena is lit by 5 lights equally spaced around the perimeter of the arena. What is the measure of each angle formed b

Artyom0805 [142]

Answer:

D. 108 degrees

Step-by-step explanation:

use the formula (n-2)180/n, n being number of sides.

In this case, the number of sides is 5.

plug it into the formula and solve:

(5-2)180/5

(3)180/5

540/5

108 degrees.

6 0

2 years ago

Read 2 more answers

which of the following is equivalent to 3 sqrt 32x^3y^6 / 3 sqrt 2x^9y^2 where x is greater than or equal to 0 and y is greater

Nutka1998 [239]

Answer:

$\frac{\sqrt[3]{16y^4}}{x^2}$

Step-by-step explanation:

The options are missing; However, I'll simplify the given expression.

Given

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$

Required

Write Equivalent Expression

To solve this expression, we'll make use of laws of indices throughout.

From laws of indices $\sqrt[n]{a} = a^{\frac{1}{n}}$

So,

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$ gives

$\frac{(32x^3y^6)^{\frac{1}{3}}}{(2x^9y^2)^\frac{1}{3}}$

Also from laws of indices

$(ab)^n = a^nb^n$

So, the above expression can be further simplified to

$\frac{(32^\frac{1}{3}x^{3*\frac{1}{3}}y^{6*\frac{1}{3}})}{(2^\frac{1}{3}x^{9*\frac{1}{3}}y^{2*\frac{1}{3}})}$

Multiply the exponents gives

$\frac{(32^\frac{1}{3}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

Substitute $2^5$ for 32

$\frac{(2^{5*\frac{1}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

$\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

From laws of indices

$\frac{a^m}{a^n} = a^{m-n}$

This law can be applied to the expression above;

$\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$ becomes

$2^{\frac{5}{3}-\frac{1}{3}}x^{1-3}*y^{2-\frac{2}{3}}$

Solve exponents

$2^{\frac{5-1}{3}}*x^{-2}*y^{\frac{6-2}{3}}$

$2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}$

From laws of indices,

$a^{-n} = \frac{1}{a^n}$ ; So,

$2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}$ gives

$\frac{2^{\frac{4}{3}}*y^{\frac{4}{3}}}{x^2}$

The expression at the numerator can be combined to give

$\frac{(2y)^{\frac{4}{3}}}{x^2}$

Lastly, From laws of indices,

$a^{\frac{m}{n} = \sqrt[n]{a^m}$ ; So,

$\frac{(2y)^{\frac{4}{3}}}{x^2}$ becomes

$\frac{\sqrt[3]{(2y)}^{4}}{x^2}$

$\frac{\sqrt[3]{16y^4}}{x^2}$

Hence,

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$ is equivalent to $\frac{\sqrt[3]{16y^4}}{x^2}$

8 0

2 years ago

Why are you allowed to move the decimal points before dividing with decimals? Explain your reasoning. I will give the brainliest

oksano4ka [1.4K]

Answer:

so you can make both your dividend and your divisor equal so you can divide

Step-by-step explanation:

4 0

1 year ago

Read 2 more answers

Mia is 7.01568 x 10^6 minutes old. Convert her age to more appropriate units using years, months, and days. Assume every other m

pshichka [43]

Answer:

There are 13 years 6 months and 12 days.

Step-by-step explanation:

Let's convert the scientific notation to standard form of minutes

7.01568x10^6 =7015680 minutes

Now, let's convert this to number of days because each day has 24*60=1440 minutes.

So, number of days in 7015680 minutes is $\frac{7015680}{1440}$ =4872 days

Now, change this 4872 days to years, months and days.

We know 1 year has 12 months and one month has 30 days.

So,

Number of years = $\frac{4872} {12*30}$ =13.53333333 years

Now, convert 0.53333333 years to months.

0.53333333*12=6.4 months.

Now, convert 0.4 months to days.

0.4* 30 =12 days.

So, there are 13 years 6 months and 12 days.

8 0

2 years ago

Anna and Hannah have \$80$80dollar sign, 80 each. Their friend offered to invest their money, promising to return a sum rrr time

sergey [27]

9514 1404 393

Answer:

2r(20r +60) = 80r^2

Step-by-step explanation:

Anna's first investment:

Anna's first return:

20r

Anna's second investment:

20r +60

Anna's second return:

r(20r +60)

Hannah's first investment:

Hannah's first return, and her second investment:

80r

Hannah's second return:

80r^2

Twice Anna's return was equal to Hannah's return:

2r(20r +60) = 80r^2

7 0

2 years ago