The histogram shows a city’s daily high temperatures recorded for four weeks. A graph shows temperature (degrees Fahrenheit) the
horizontal axis numbered 0 to 65 and number days on the vertical axis is numbered 1 to 5. 1 day was 0 to 5 degrees. 0 days were 5 to 10 degrees. 1 day was 10 to 15 degrees. 0 days were 15 to 20 degrees. 1 day was 20 to 25 degrees. 3 days were 25 to 30 degrees. 2 days were 30 to 35 degrees. 5 days were 35 to 40 degrees. 5 days were 40 to 45 degrees. 2 days were 45 to 50 degrees. 5 days were 50 to 55 degrees. 3 days were 55 to 60 degrees. 0 days were 60 to 65 degrees. Which phrase describes the shape of the temperature data? symmetrical left-skewed right-skewed normal
Time is a continuous variable. The minimum sleep time per night per subject here, is given as 1 minute.
Larger sleep times could be 1.08 minutes, 2.99 minutes, and other continuous/infinite values. Remember there are 60seconds in a minute and in-between seconds, there are milliseconds. So time is a continuous variable.
In this case though, our measurement of time is given in whole number units (integers). Our precision of measurement is 1 unit. We have an observed value of 180 minutes (the first subject's sleep time). The real limits of this value are 179.5 to 180.5
The simplest fraction for is . Write the upper bound as a fraction with the same denominator:
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Hence the range for would be:
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If the denominator of is also , then the range for its numerator (call it ) would be . Apparently, no whole number could fit into this interval. The reason is that the interval is open, and the difference between the bounds is less than .
To solve this problem, consider scaling up the denominator. To make sure that the numerator of the bounds are still whole numbers, multiply both the numerator and the denominator by a whole number (for example, 2.)
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At this point, the difference between the numerators is now . That allows a number ( in this case) to fit between the bounds. However, can't be written as finite decimals.
Try multiplying the numerator and the denominator by a different number.
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It is important to note that some expressions for can be simplified. For example, because of the common factor .