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Mashcka [7]
2 years ago
8

A toy airplane climbs 30 vertical feet while traveling 50 feet horizontally. A toy helicopter climbs 20 feet while traveling 40

feet horizontally. Assuming a steady rate of change, which toy traveled at a greater slope?
answers
The airplane did, because Three-fifths greater-than one-half.
The airplane did, because Five-thirds greater-than 2.
The helicopter did, because 2 greater-than five-thirds.
The helicopter did, because One-half greater-than three-fifths.
Mathematics
2 answers:
PilotLPTM [1.2K]2 years ago
8 0

Answer:

Slope is the change in y over the change in x. The toy airplane would then have a slope of 3/5 and the toy helicopter would have a slope of 1/2. As 3/5 is greater than 1/2, the toy airplane would have a greater slope.

Hope this helps!

Step-by-step explanation:

Mark me as brainliest pls :)

professor190 [17]2 years ago
6 0

Answer:

Slope is the change in y over the change in x. The toy airplane would then have a slope of 3/5 and the toy helicopter would have a slope of 1/2. As 3/5 is greater than 1/2, the toy airplane would have a greater slope.

Step-by-step explanation:

meep

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Three times the sum of half Carlita’s age and 3 is at least 12.What values represent Carlita’s possible age? graph the solution
gulaghasi [49]

<em><u>3 x 12 </u></em>

<em><u>I think because you find out how to graph in the corresponding area on the graph </u></em>

5 0
2 years ago
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Tony is 4 years younger than his brother josh and two years older than his sister Cindy. Tony also has a twin brother, Evan. All
Sholpan [36]

Let Tony's age = x

He is 4 years younger than his brother Josh, so Josh's age would be x + 4

He is 2 years older than his sister, so her age would be x - 2

He has a twin, which would be the same age, so the twins age is also x

They all add together to equal 66, so you get:

x  + x + x+4 + x-2 = 66

Simplify:

4x +2 = 66

Subtract 2 from both sides:

4x = 64

Divide both sides by 4:

x = 64/4 = 16

Tony is 16 years old.

8 0
2 years ago
Which expression is equivalent to StartFraction (5 a b) cubed Over 30 a Superscript negative 6 Baseline b Superscript negative 7
lorasvet [3.4K]

Answer: \frac{25}{6} a^{9} b^{10}

Step-by-step explanation:

Assuming the described expression is:

\frac{(5ab)^{3}}{30 a^{-6} b^{-7}}

And knowing the condition a \neq 0 and b \neq 0

We cansimplify it following the rules related to the exponents with the same base:

\frac{25}{6} a^{3} b^{3} a^{6} b^{7}

Finally:

\frac{25}{6} a^{9} b^{10}

3 0
2 years ago
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The coordinate plane shows the outline of a town park. A bike path is to be constructed that runs directly through the park from
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Answer:

20

Step-by-step explanation:

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4 0
2 years ago
A square based brass plate in 4mm high and has a mass of 1.05kg. The density of the brass is 4.2g/cm3, calculate the length of t
Bezzdna [24]

Answer:

Length = 25cm

Step-by-step explanation:

Given

Brass Shape: Square

Density = 4.2g/cm^3

Mass = 1.05kg

Height = 4mm

Required

Determine the length of the plate

First, we need to calculate the Volume of the Brass using

Density = \frac{Mass}{Volume}

Make Volume the subject of formula

Volume = \frac{Mass}{Density}

Substitute 1.05kg for Mass and 4.2g/cm³ for Density

Volume = \frac{1,05\ kg}{4.2\ g/cm^3}

Convert 1.05 kg to grams

Volume = \frac{1.05 * 1000\ kg}{4.2\ g/cm^3}

Volume = \frac{1050 \ kg}{4.2\ g/cm^3}

Volume = \frac{1050 \ kg}{4.2\ g/cm^3}

Volume = 250cm^3

Next is to determine the Area of the brass;

Volume = Height * Area

Substitute 250cm³ for Volume and 4mm for Height

250cm^3 = 4mm * Area

Convert mm to cm

250cm^3 = 4 * 0.1cm * Area

250cm^3 = 0.4cm * Area

Divide both sides by 0.4cm

\frac{250cm^3}{0.4cm} = \frac{0.4cm * Area}{0.4cm}

\frac{250cm^3}{0.4cm} =Area

625cm^2 = Area

Area = 625cm^2

Lastly, we'll calculate the length of the brass

Since the brass is square based;

Area = Length^2

Substitute 625cm² for Area

625cm^2 = Length^2

Take square root of both sides

\sqrt{625cm^2} = Length

25cm = Length

Length = 25cm

<em>Hence, the length of the square brass is 25cm</em>

5 0
2 years ago
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