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2 years ago

The rule is applied to trapezoid ABCD to produce the final image A"B"C"D".

Mathematics

2 answers:

motikmotik2 years ago

8 0

Answer: (-1, 0) (-1, -5)

Step-by-step explanation:

Fantom [35]2 years ago

6 0

Answer:

(-1,0) (-1,-5)

Step-by-step explanation:

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Using approximations to 1 significant figure check that your answer to part a makes sense

natka813 [3]

Answer:

A significant figure is the first digit in a number that isn't zero. You round to this.

Step-by-step explanation:

E.g. 1959302 to 1 Sig Fig = 2000000

You round to the first figure that isn't zero, which is one

E.g 0.000001373 to 1 Sig Fig = 0.000001 because that 1 is the first digit that isn't zero

3 0

2 years ago

Allan is ordering a set of rational numbers that includes positive values, negative values, fractions, and decimal numbers. How

Marianna [84]

By doing least to greatest

7 0

2 years ago

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Given the general identity tan X =sin X/cos X , which equation relating the acute angles, A and C, of a right ∆ABC is true?

irakobra [83]

First, note that $m\angle A+m\angle C=90^{\circ}.$ Then

$m\angle A=90^{\circ}-m\angle C \text{ and } m\angle C=90^{\circ}-m\angle A.$

Consider all options:

$\tan A=\dfrac{\sin A}{\sin C}$

By the definition,

$\tan A=\dfrac{BC}{AB},\\ \\\sin A=\dfrac{BC}{AC},\\ \\\sin C=\dfrac{AB}{AC}.$

Now

$\dfrac{\sin A}{\sin C}=\dfrac{\dfrac{BC}{AC}}{\dfrac{AB}{AC}}=\dfrac{BC}{AB}=\tan A.$

Option A is true.

$\cos A=\dfrac{\tan (90^{\circ}-A)}{\sin (90^{\circ}-C)}.$

By the definition,

$\cos A=\dfrac{AB}{AC},\\ \\\tan (90^{\circ}-A)=\dfrac{\sin(90^{\circ}-A)}{\cos(90^{\circ}-A)}=\dfrac{\sin C}{\cos C}=\dfrac{\dfrac{AB}{AC}}{\dfrac{BC}{AC}}=\dfrac{AB}{BC},\\ \\\sin (90^{\circ}-C)=\sin A=\dfrac{BC}{AC}.$

Then

$\dfrac{\tan (90^{\circ}-A)}{\sin (90^{\circ}-C)}=\dfrac{\dfrac{AB}{BC}}{\dfrac{BC}{AC}}=\dfrac{AB\cdot AC}{BC^2}\neq \dfrac{AB}{AC}.$

Option B is false.

$\sin C = \dfrac{\cos A}{\tan C}.$

By the definition,

$\sin C=\dfrac{AB}{AC},\\ \\\cos A=\dfrac{AB}{AC},\\ \\\tan C=\dfrac{AB}{BC}.$

Now

$\dfrac{\cos A}{\tan C}=\dfrac{\dfrac{AB}{AC}}{\dfrac{AB}{BC}}=\dfrac{BC}{AC}\neq \sin C.$

Option C is false.

$\cos A=\tan C.$

By the definition,

$\cos A=\dfrac{AB}{AC},\\ \\\tan C=\dfrac{AB}{BC}.$

As you can see $\cos A\neq \tan C$ and option D is not true.

$\sin C = \dfrac{\cos(90^{\circ}-C)}{\tan A}.$

By the definition,

$\sin C=\dfrac{AB}{AC},\\ \\\cos (90^{\circ}-C)=\cos A=\dfrac{AB}{AC},\\ \\\tan A=\dfrac{BC}{AB}.$

Then

$\dfrac{\cos(90^{\circ}-C)}{\tan A}=\dfrac{\dfrac{AB}{AC}}{\dfrac{BC}{AB}}=\dfrac{AB^2}{AC\cdot BC}\neq \sin C.$

This option is false.

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2 years ago

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What is the constant of proportionality in the equation y = StartFraction x over 9 EndFraction? 0 StartFraction 1 over 9 EndFrac

Sonja [21]

Answer:

The answer is C.

Step-by-step explanation:

You only need the answer.

8 0

2 years ago

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To bill customers for water usage, one city converts the number of gallons used into units. This relationship is represented by

Anastaziya [24]

We are given equation g = 748u, where g is the total number of gallons of water used and u is the number of units.

We can see that the number of units of water being used by customers.

The number of units of water doesn't depend on the total number of gallons of water used.

Therefore, the number of units u is an independent variable.

The value of the total number of gallons is totally depends on the number of units used.

Therefore, the total number of gallons of water used g is a dependent variable.

So, we can conclude following statements:

1) g is the dependent variable.

2) u is the independent variable.

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2 years ago

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