<span>The expression given (27x^2)z/(-3x^2)(z^6), can be simplify as below:
By properties of powers, if you have the same base, you can substract the exponents. Then:
=(</span>27x^2)z/(-3x^2)(z^6)
=-9z/z^6 (As you can see: x^2-2= x^0=1)
=-9/z^5 (Then, z^6-1=z^5)
<span>
Therefore, the answer is: The exponent on the variable z is 5.</span>
A^2 + b^2 = c^2...a and b are the legs and c is the hypotenuse
20^2 + 21^2 = c^2
400 + 441 = c^2
841 = c^2
sqrt 841 = c
29 = c <== third straw will be 29 cm
9^ ? 3^2 + 7^2
81 ? 9 + 49
81 > 58
c^ > a^2 + b^2
answer is obtuse triangle
Answer:
So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.
Step-by-step explanation:
The height h of the ball is modeled by the following equation

The problem want you to find the times the ball will be 48 feet above the ground.
It is going to be when:





We can simplify by 16t. So

It means that
16t = 0
t = 0
or
t - 2 = 0
t = 2
So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.
Answer:
true
Step-by-step explanation: