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NeX [460]
2 years ago
10

A heat pump operates on a Carnot heat pump cycle with a COP of 12.5. It keeps a space at 24°C by consuming 2.15 kW of power. Det

ermine the temperature of the reservoir from which the heat is absorbed and the heating load provided by the heat pump.
Engineering
1 answer:
Vinil7 [7]2 years ago
4 0

Answer:

a) T_{L} = 273.378\,K\,(0.228\,^{\textdegree}C), b) \dot Q_{H} = 26.875\,kW

Explanation:

a) The Coefficient of Performance of the Carnot Heat Pump is:

COP_{HP} = \frac{T_{H}}{T_{H}-T_{L}}

After some algebraic handling, the temperature of the cold reservoir is determined:

T_{H}-T_{L} = \frac{T_{H}}{COP_{HP}}

T_{L} = T_{H}\cdot \left(1-\frac{1}{COP_{HP}}  \right)

T_{L} = (297.15\,K)\cdot \left(1-\frac{1}{12.5}\right)

T_{L} = 273.378\,K\,(0.228\,^{\textdegree}C)

b) The heating load provided by the heat pump is:

\dot Q_{H} = COP_{HP}\cdot \dot W

\dot Q_{H} = (12.5)\cdot (2.15\,kW)

\dot Q_{H} = 26.875\,kW

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The closed tank of a fire engine is partly filled with water, the air space above being under pressure. A 6 cm bore connected to
skelet666 [1.2K]

Answer:

The air pressure in the tank is 53.9 kN/m^{2}

Solution:

As per the question:

Discharge rate, Q = 20 litres/ sec = 0.02\ m^{3}/s

(Since, 1 litre = 10^{-3} m^{3})

Diameter of the bore, d = 6 cm = 0.06 m

Head loss due to friction, H_{loss} = 45 cm = 0.45\ m

Height, h_{roof} = 2.5\ m

Now,

The velocity in the bore is given by:

v = \frac{Q}{\pi (\frac{d}{2})^{2}}

v = \frac{0.02}{\pi (\frac{0.06}{2})^{2}} = 7.07\ m/s

Now, using Bernoulli's eqn:

\frac{P}{\rho g} + \frac{v^{2}}{2g} + h = k                  (1)

The velocity head is given by:

\frac{v_{roof}^{2}}{2g} = \frac{7.07^{2}}{2\times 9.8} = 2.553

Now, by using energy conservation on the surface of water on the roof and that in the tank :

\frac{P_{tank}}{\rho g} + \frac{v_{tank}^{2}}{2g} + h_{tank} = \frac{P_{roof}}{\rho g} + \frac{v_{tank}^{2}}{2g} + h_{roof} + H_{loss}

\frac{P_{tank}}{\rho g} + 0 + 0 = \0 + 2.553 + 2.5 + 0.45

P_{tank} = 5.5\times \rho \times g

P_{tank} = 5.5\times 1\times 9.8 = 53.9\ kN/m^{2}

4 0
2 years ago
CHALLENGE ACTIVITY 1.4.1: Basic syntax errors. Type the statements. Then, correct the one syntax error in each statement. Hints:
Lunna [17]

Answer:

Lets check each statement for the errors.

Explanation:

System.out.println("Predictions are hard.");

This statement has no syntax errors. When this statement is executed the following line will be displayed:

Predictions are hard.

System.out.print("Especially ');

This statement is missing the closing quotation mark. A single quotation mark is placed instead of double quotation mark in the statement.

The following error message will be displayed when this program statement will be compiled:

Main.java:15: error: unclosed string literal

String literals use double quotes. So to correct this syntax error, the statement should be changed as follows:

System.out.print("Especially");

The output of this corrected line is as following:

Especially

System.out.println("about the future.").

In this line a period . is placed at the end of the statement instead of a semicolon ; but according to the syntax rules statements should end in semicolons.

The error message displayed when this line is compiled is as following:

Main.java:15: error: ; expected

Main.java:15: error: not a statement

So in order to correct this syntax error the statement should be changed as following:

System.out.println("about the future.");    

The output of this corrected line is as following:

about the future

System.out.println("Num is: " - userName);

There is a syntax error in this statement because of - symbol used instead of +

+ symbol is used to join together a variable and a value a variable and another variable in a single print statement.

The error message displayed when this line is compiled is as following:

Main.java:13: error: bad operand types for binary operator '-'

So in order to correct this syntax error the statement should be changed as following:

System.out.println("Num is: " + userName);

This line will print two things one is the string Num is and the other is the value stored in userName variable.

So let userName= 5 then the output of this corrected line is as following:

Num is: 5

8 0
2 years ago
Explain why the fundamental software engineering principles of process, dependability, requirements management, and reuse are re
Svet_ta [14]

Answer:

1. Costs and frequency of change.

2. The most important ‘non-functional’ requirements. Different systems have different priorities for non-functional requirements.

3. The software lifetime and delivery schedule.

Explanation:

The process of requirement gathering is required in both generic and customized software.

• A document to define the development process is required in all type of software application.

• Updating is required in each type of software. For doing so, new version of each type of software is released.

• Maintenance is an important part of software development. It is required in each type of application development.

• Software has some minimum requirements to execute. So, platform dependability is considered in all software development.

5 0
2 years ago
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Given an array of words representing your dictionary, you test words to see if it can be made into another word in dictionary. T
katen-ka-za [31]

Answer:

Detailed solution is given below:

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2 years ago
mechanically cleaned wastewater bar screen is constructed using 6.5-mm-wide bars spaced 5.0 cm apart center to center; the bars
Annette [7]

Answer: The head loss is 1.5 cm

Explanation:  Equation needed to solve is: h= (vs^2-v^2)/2gC^2

where C is the friction coefficient. To determine the area of flow, we nee to realize that the area available for flow over an area of 1*1 m, Aₓ= 0.87 m², observed from the correlation that for every width of 5.0 cm, we lose 6.5 mm, roughly about 12.9 or 13%.

For a fresh clean screen, the velocity will tend to increase by a factor of  (1/0.87).

The velocities through the screen equals to (0.4/0.87) = 0.46 m/s and (0.8/0.87) = 0.92 m/s.

Apply the above mentioned equation:

h= (0.92^2-0.8^2)/2*0.84^2*9.81 \\\\=0.01499\\=0.015 m = 0.015*100 = 1.50 cm

6 0
2 years ago
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