A dc shunt generator rated at 85 kW produces a voltage of 280 V. The brush voltage drop is 2.5 V, and the armature and field res
istances are 0.09 Ω and 115 Ω, respectively. The generator delivers rated current at rated speed and rated voltage. (a) Calculate the field, armature, and load currents versus load. Test the equations with the rated load. (b) Determine the terminal voltage at no-load and at rated load conditions. (c) Calculate the voltage regulation of the generator. Use the no-load voltage as the base value. (d) Plot the terminal voltage as a function of the load. Determine the load that corresponds to a 5% voltage drop using the no-load voltage as the base
1 answer:
Answer:
(a) Calculate the field, armature, and load currents versus load = 306A
(b) Determine the terminal voltage at no-load and at rated load conditions = 300V
(c) Calculate the voltage regulation of the generator. Use the no-load voltage as the base value = 6.67%
(d) Plot the terminal voltage as a function of the load. Determine the load that corresponds to a 5% voltage drop using the no-load voltage as the base = 294.74V
Explanation:
CHECK THE ATTACHED FILES FOR DETAILED EXPLANATION.
You might be interested in
Answer:
Explanation:
Hello,
a. On the attached document, you can see a brief scheme of the process. Thus, to know the degrees of freedom, we state the following unknowns:
- and
: extent of the reactions (2).
- ,
,
,
and
: Molar flows at the second stream (5).
On the other hand, we've got the following equations:
- : oxygen mole balance.
- : methane mole balance.
- : water mole balance.
- : formaldehyde mole balance.
- : carbon dioxide mole balance.
Thus, the degrees of freedom are:
It means that we need two additional equations or data to solve the problem.
b. Here, the two missing data are given. For the fractional conversion of methane, we define:
And for the fractional yield of formaldehyde we can set it in terms of methane as the reagents are equimolar:
In such a way, one realizes that the output formaldehyde's molar flow is:
Which is equal to the first reaction extent , therefore, one computes the second one from the fractional conversion of methane as:
Now, one computes the rest of the output flows via:
-
-
-
-
-
The total output molar flow is:
Therefore the output stream composition turns out into:
Best regards.
Answer:
Magnitude of force P = 25715.1517 N
Explanation:
Given - The wires each have a diameter of 12 mm, length of 0.6 m, and are made from 304 stainless steel.
To find - Determine the magnitude of force P so that the rigid beam tilts 0.015∘.
Proof -
Given that,
Diameter = 12 mm = 0.012 m
Length = 0.6 m
= 0.015°
Youngs modulus of elasticity of 34 stainless steel is 193 GPa
Now,
By applying the conditions of equilibrium, we have
∑fₓ = 0, ∑ = 0, ∑M = 0
If ∑ = 0
⇒×0.9 - P × 0.6 = 0
⇒×3 - P × 2 = 0
⇒ =
If ∑ = 0
⇒×0.9 = P × 0.3
⇒ ×3 = P
⇒ =
Now,
Area, A = = 1.3097 × 10⁻⁴ m²
We know that,
Change in Length , =
Now,
= 9.1626 × 10⁻⁹ P
= 1.83253 × 10⁻⁸ P
Given that,
= 0.015°
⇒ = 2.618 × 10⁻⁴ rad
So,
⇒2.618 × 10⁻⁴ = ( 1.83253 × 10⁻⁸ P - 9.1626 × 10⁻⁹ P) / 0.9
⇒P = 25715.1517 N
∴ we get
Magnitude of force P = 25715.1517 N
Answer:
The endurance strength for the rod is 434.6 MPa
Explanation:
Since the rod is used in rotating bending, we need to use Marin equation given by
Here S stands for the endurance strength for rotating bending, is the endurance strength, and
are the parameters for Marin surface modification factor.
Endurance strength.
We can start finding the endurance strength, from the directions we know that the hardness was found to be 300 Brinell, thus for such value we can find the ultimate tensile strength using
Replacing the hardness we get
Now since the ultimate tensile strength has a value less than 1400 MPa, we can find the endurance strength using
Replacing the tensile strength we get
Parameters for Marin surface modification factor.
From the directions we know that the drill rod has a ground surface finish, so then from tables we get
Thus the surface factor will be
Replacing values and the ultimate tensile strength
Then we can find the rotating shaft factor, for a diameter of 10 mm, we can use the equation
Replacing the diameter we get
Estimating endurance strength for rotating shaft.
We can replace now all values we have found in Marin equation.
Thus the endurance strength for the rod is 434.6 MPa