4a2 + 4a + 1 = (2a +1)^2 = <span>(2a + 1)(2a + 1)
</span>4 − 4a + a2 = (2 - a)^2 = <span>(2 − a)(2 − a)
</span>4a2 − 4a + 1 = (2a -1)^2 = <span>(2a − 1)(2a − 1)
</span><span>4 + 4a + a2</span> = (2 + a)^2 = (2 + a)(2 + a)
Answer:
x=y
Step-by-step explanation:
There is exactly one value of x for a value of the function by the one-to-one property.
Answer: The first experiment has M probabilities, and the second has I(m) outcomes, that depends on the result of the first.
And lets call m to the result of the first experiment.
If the outcome of the first experiment is 1, then the second experiment has 1 possible outcome.
If the outcome of the first experiment is 2, then the second experiment has 2 possibles outcomes.
If the outcome of the first experiment is M, then the second experiment has M possibles outcomes.
And so on.
So the total number of combinations C is the sum of all the cases, where we exami
1 outcome for m = 1
+
2 outcomes for m=2
+
.
.
.
+
M outcomes for m = M
C = 1 + 2 + 3 + 4 +...´+M
