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antoniya [11.8K]
1 year ago
13

Suppose that of a cohort of 150 mice in a mouse colony born in February, 125 are still at the end of March and 115 are still ali

ve at the end of April. What is the survivorship up to the start of April? Round to the nearest hundredth.
Biology
1 answer:
kogti [31]1 year ago
5 0

Answer: Survival rate up to start of April = 76.67%

Explanation: size of colony = 150mice.

Size of colony in February =125mice.

Size of colony in march = 115 mice.

1. Survivorship rate in February

= Size of colony / size in February *100.

= 122 / 150 * 100

= 83.33% to the nearest hundredth

2. Survivorship rate in march

= Size of colony / size in march *100.

= 115/150 * 100

= 76.67% to the nearest hundredth.

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Answer:

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Answer:True

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6 0
1 year ago
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adell [148]

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3 0
1 year ago
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In order to calculate the distance between two alleles/genes that are found in the same chromosome, we need to know how often crossing-over happened (recombination frequency). We know from the text that white eyes were linked to miniature wings and that wild type eyes were linked to wild type wings, so any phenotype that's contrary to these parent combinations are a result of crossing-over. We know then that 230 flies + 240 flies were a result of such recombination. To calculate the recombination frequency we only need to divide these flies (total of recombinant flies) by the total of flies in the offspring and turn it into percentage.
\frac{230+240}{1000}=0.47
0.47*100%=47%
47 map units is the distance between the genes <span>for eye color and wing length.</span>
7 0
2 years ago
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