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Kamila [148]
2 years ago
12

Match each organism with the type of association it exhibits. (letters to numbers)

Biology
2 answers:
Reil [10]2 years ago
6 0
B is prey predator

C is parasitism

A is commensalism
Nutka1998 [239]2 years ago
6 0

Ans.

Biological interactions or ecological interactions are defined as relationships that affect two organisms of same or different species living in a community. Different types of association are observed in different organisms.

Barnacles and whale show a type of symbiotic relationship, in which barnacles get benefit from association, without causing any harm to whale. This type of association is known as commensalism. Thus, option A). correctly matches with option 3). commensalism.

A stork and fish shows prey-predator relationship, where stork is predator that feeds on small fishes (preys). In this kind of relationship one species gets benefits, while other gets harm. Thus, option B). correctly matches with option 1). prey-predator.

A tick sucking the blood from an animal body shows a kind of symbiotic association, known as parasitism. The tick (parasite) lives inside inside or on the body of another organism (host) to get benefit and causes harm to the host. Thus, option C). correctly matches with option 2). parasitism.

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2 years ago
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Develop a hypothesis to explain why you think eurypterids developed legs even though they lived on the ocean floor.
expeople1 [14]

I think that since it lives on the ocean floor, at the deepest of the ocean. So anyway, the fin on the Eurypterids is still necessary but not that much, since they live on the ocean floor. Their movements mostly on the ocean floor. So fin would not help them "stick" to the floor. Also there are still gravity acts on the Eurypterids and the feet would help them move faster. Hope this helps.

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2 years ago
Consider a population of frogs. Allele B1 codes for spotted frogs; allele B2 codes for non-spotted frogs. B1 is dominant to B2 .
oee [108]

Answer:

Frequency of B1 = 0.47

Frequency of B2 = 0.53

Hope this helps!

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2 years ago
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In horses, the Overo gene, Ov, produces a white splotch pattern on the coat. The overo phenotype is seen only when a horse has o
Anuta_ua [19.1K]

The question is incomplete. Here is the complete question.

In horses, the Overo gene, <em>Ov</em>, produces a white splotch pattern on the coat. The overo phenotype is seen only when a horse has one Ov copy, <em>Ovov</em>. Horses with two <em>Ov</em> copies, <em>OvOv</em>, die soon after birth are called white overo because they are completely white. Horses with no <em>Ov </em>copies are solid colored, <em>ovov</em>.

The Leopard complex gene, <em>Lp</em>, shows incomplete dominance and controls white spotting. One <em>Lp </em>allele, <em>Lplp</em>, produces the leopard phenotype, in which there are spots everywhere. Two <em>Lp</em> alleles, <em>LpLp</em>, produce the fewspot phenotype, in which the horse is mostly white with colored spots.

A horse that is both overo and leopard is called pintaloosa, and these horses are spotted with splotches. A horse that is overo and fewspot is considered fewspot because the white areas from <em>Lp</em> is indistinguishable from the white from <em>Ov</em>.

Suppose that 16 pairs of pintaloosa horses have one offpring per pair. How many each phenotype would be expected? Determine the number out of 16 expected for each phenotype. Only count phenotypes of offspring expected to live past one week of age.

overo:

white overo:

fewspot:

Answer: Overo: 2

              White overo: 0

              Fewspot: 3

Explanation: Pintaloosa is a "combination" of overo and leopard, so the pair's genotype is OvovLplp.

To cross a pair, use Punnet Square and to facilitate, use the square for each characteristics:

Punnett Square For overo and white overo:

          Ov             ov

Ov    OvOv        Ovov

ov    Ovov          ovov

Analysing this Punnett square, notice that there are 2 individuals who will carry the genotype for overo (Ovov) phenotype. So, 2 out of the 16 pair will have an overo phenotype.

Since white overo is recessive (ovov) and doesn't survive past birth, there will be zero horses with that phenotype.

Punnett Square For leopard and fewspot:

          Lp         lp

Lp    LpLp      Lplp

lp     Lplp       lplp

From this square, notice that there are 1 individual who is fewspot. However, a horse that is overo <u>and</u> fewspot is considered fewspot, so for the 16 pair, 3 out 16 will be fewspot.

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nikdorinn [45]

Answer:

Inhibit control over ions.

Explanation:

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