Answer:
Option D, 75%
Explanation:
Let the genotype of co dominant checkered hen mates and checkered rooster be CcC and CcC
Where Cc – is the allele for chekered skin
C – is the allele for non chekered skin
Co-dominant allele are those which irrespective of being dominant or recessive are expressed equally.
The punnet square for the cross between these two would be
Cc C
Cc CcCc CcC
C CCc CC
3 out of 4 offsprings have chekered allele i.e CcCc, CcC and CcC. Thus, the probability of chekered offsprings would be 75%
Weathering (erosion), transportation, deposition, compaction. Essentially D is the correct answer.
Due to the definition of the central dogma, another way of putting it is that the central dogma follows the flow of information from DNA to protein.
Answer:
2.Less than 73% of the populations would have only one allele present.
Explanation:
The two alleles chosen do not affect the fitness of flies in the lab environment, so Kerr and Wright could be confident that if changes in the frequency of normal and forked phenotypes occurred, they would not be due to natural selection.
Using a larger breeding population would not be expected to alter the outcome of the experiment.
