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arlik [135]
2 years ago
4

A scientist calculated the mean and standard deviation of a data set to be Mu = 120 and Sigma = 9. She then found that she was m

issing one data value from the set. She knows that the missing data value was exactly 3 standard deviations away from the mean. What was the missing data value?
Mathematics
2 answers:
max2010maxim [7]2 years ago
7 0

Answer:

The missing data value is 147

Step-by-step explanation:

The mean is 120

The standard deviation is 9

Missing data value = ?

From the question, the missing data value is 3 standard deviation away from the mean.

3 standard deviation = 3 * 9 = 27

3 standard deviation from the mean = 120 + 27 = 147

The missing data value is what we get after adding 3 standard deviation from the mean.

Away here means ahead which is sum.

Anna007 [38]2 years ago
5 0

Answer:

b on edg

Step-by-step explanation:

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How many 9’s are there between 1 and a 100?
OleMash [197]

Answer:

20

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
. For each of these intervals, list all its elements or explain why it is empty. a) [a, a] b) [a, a) c) (a, a] d) (a, a) e) (a,
Eva8 [605]

Answer:

Elements are of the form

 (i) [a,a]=\{[x,y] : a\leq x\leq a, a\leq y\leq a; a\in \mathbb R\}

(ii) [a,b)=\{[x,y) :a\leq x

(iii)(a,a]=\{(x,y] :a

(iv)(a,a)=\{(x,y): a

(v) (a,b) where a>b=\{(x,y) : a>x>b,a>y>b;a>b,a,b \in \mathbb R\}

(vi) [a,b] where a>b=\{[x,y] : a\geq x\geq b,a\geq y\geq b;a>b,a,b \in \mathbb R\}

Step-by-step explanation:

Given intervals are,

(i) [a,a] (ii) [a,a) (iii) (a,a] (iv) (a,a) (v) (a,b) where a>b (vi)  [a,b] where a>b.

To show all its elements,

(i) [a,a]

Imply the set including aa from left as well as right side.

Its elements are of the form.

\{[a,a] : a\in \mathbb R\}=\{[0,0],[1, 1],[-1,-1],[2,2],[-2,-2],[3,3],[-3,-3],........\}

Since there is a singleton element a of real numbers, this set is empty.

Because there is no increment so if a\in \mathbb R then the set  [a,a] represents singleton sets, and singleton sets are empty so is [a,a].

(ii) [a,a)

This means given interval containing a by left and exclude a by right.

Its elements are of the form.

[ 1, 1),[-1,-1),[2,2),[-2,-2),[3,3),[-3,-3),........

Since there is a singleton element a of real numbers withis the set, this set is empty.

Because there is no increment so if a\in \mathbb R then the set  [a,a) represents singleton sets, and singleton sets are empty so is [a.a).

(iii) (a,a]

It means the interval not taking a by left and include a by right.

Its elements are of the form.

( 1, 1],(-1,-1],(2,2],(-2,-2],(3,3],(-3,-3],........

Since there is a singleton element a of real numbers, this set is empty.

Because there is no increment so if a\in \mathbb R then the set  (a,a] represents singleton sets, and singleton sets are empty so is (a,a].

(iv) (a,a)

Means given set excluding a by left as well as right.

Since there is a singleton element a of real numbers, this set is empty.

Its elements are of the form.

( 1, 1),(-1,-1],(2,2],(-2,-2],(3,3],(-3,-3],........

Because there is no increment so if a\in \mathbb R then the set  (a,a) represents singleton sets, and singleton sets are empty, so is (a,a).

(v) (a,b) where a>b.

Which indicate the interval containing a, b such that increment of x is always greater than increment of y which not take x and y by any side of the interval.

That is the graph is bounded by value of a and it contains elements like it we fixed a=5 then,

(a,b)=\{(5,0),(5,1),(5,2).....\} e.t.c

So this set is connected and we know singletons are connected in \mathbb R. Hence given set is empty.

(vi) [a,b] where a\leq b.

Which indicate the interval containing a, b such that increment of x is always greater than increment of y which include both x and y.

That is the graph is bounded by value of a and it contains elements like it we fixed a=5 then,

[a,b]=\{[5,0],[5,1],[5,2].....\} e.t.c

So this set is connected and we know singletons are connected in \mathbb R. Hence given set is empty.

8 0
2 years ago
Which of the following equations could describe a square pyramid? Select all that apply.
Katena32 [7]

C. w= 3V/lh

D. V/B=h/3

E. V=w^2h/3

4 0
2 years ago
The exponential distribution can be used to solve Poisson-type problems in which the intervals are not time. The Air Travel Cons
frutty [35]

Answer:

a) P(X \ge 490) = 0.628

b) P(X \leq 190) = 0.165

Step-by-step explanation:

a) This is an exponential distribution question since it is a poisson type problem

Mean rate is 0.95 per 1000 passengers

Mean rate, \lambda = 0.95/1000

\lambda = 0.00095 per passenger

Probability that at least 490 passengers will have their baggage handled properly before the next mishandling occurs :

P(X \ge x) = e^{- \lambda x}

P(X \ge 490) = e^{-490 * 0.00095}

P(X \ge 490) = e^{-0.4655}\\P(X \ge 490) = 0.628

b)  Probability that the number will be fewer than 200 passengers

P(X \leq 190) = 1 - P(X \geq 190)\\P(X \leq 190) = 1 - e^{-190 \lambda} \\P(X \leq 190) = 1 - e^{-190 *0.00095}

P(X \leq 190) = 1 - 0.835\\P(X \leq 190) = 0.165

8 0
2 years ago
John spends $2.75 on donuts for his office employees every weekday. On Sunday mornings he takes his wife and kids to the donut s
Airida [17]

Answer:

(d)- $26.74

Step-by-step explanation:

John spends $2.75 on donuts for his office employees every weekday. On Sunday mornings he takes his wife and kids to the donut shop and spends $12.99. How much money does John spend on donuts throughout the week?

a) $23.24

b) $19.64

c) $29.14

d) $26.74

3 0
2 years ago
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