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Blababa [14]
2 years ago
11

Suppose the demand function for avocados is Q = 104 - 40p + 20tp + 0.01Y, where p is the price of avocados, pt is the price of t

omatoes, and Y is average income, and the supply function for avocados is Q = 58 + 15p - 20pf, where pf is the price of fertilizer. Suppose pt = $0.80, Y = $4,000, and pf = $0.40. What is the equilibrium price and quantity of avocados? The equilibrium price of avocados is = $2.00 and the equilibrium quantity is Q = 80 units Suppose the government charges a $0.55 specific tax per avocado to be paid by consumers. With the tax, the equilibrium price of avocados is p = $1.60 and the equilibrium quantity is Q = 74 units.
Business
1 answer:
LiRa [457]2 years ago
8 0

Answer: equilibrium price = 4

Quantity of avocado = 110units

Explanation:

Q = 104 - 40p + 20tp + 0.01Y........eq1

Q = 58 + 15p - 20pf...........eq2

pt = $0.80,

Y = $4,000,

pf = $0.40

From eqn1 substituting of into it

Q = 104 - 40p + 20($0.80) + 0.01($4000)

= 104 - 40p + 16 + 40

= 160/40p

p = 4 equilibrium price

From eqn2. Substituting p and pf into it.

Q = 58 + 15p - 20pf

Q = 58 + 15(4) - 20($0.40).

Q = 58 + 60 - 8

Q = 110 quantity of avocado

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A catering company prepared and served 350 meals at an anniversary celebration last week using 8 workers. The week before, 2 wor
pav-90 [236]

Answer:

Labour productivity at an anniversary celebration = 43.75

Labour productivity  at a wedding reception = 115

Labour productivity is higher at the wedding reception.

Explanation:

Labour productivity is the ratio of output to labour

Labour productivity at an anniversary celebration = 350 / 8 = 43.75

Labour productivity  at a wedding reception = 230 / 2 = 115

Labour productivity is higher at the wedding reception. Less labour produces more more meals.

This can be explained by the law of diminishing marginal returns

the law of diminishing returns states that as more units of a variable input is added to a fixed income of production, output might increase at a point but after some time total output would increase at a decreasing rate and marginal product would be decreasing.

3 0
2 years ago
Paddy has lots of cousins. With a family reunion in the near future, Paddy decides to collect income information for himself and
Trava [24]

Answer:

37.9%, lower

Explanation:

Paddy has lots of cousins. With a family reunion in the near future, Paddy decides to collect income information for himself and all his cousins. He obtains the following data points: $52,000, $22,000, $92,000, $8,000, $118,000, $62,000, $38,000, $14,000, $132,000, $46,000, $26,000, $96,000, $54,000, $110,000, $80,000. The share of income received by the highest quintile of this income distribution is <u>37.9%</u>, which is <u>lower</u> than that for the highest quintile of the U.S. income distribution in 2005.

8 0
2 years ago
A stock is priced at $85 per share and pays a quarterly dividend of $2.10 per share. What is the dividend yield per stock share
Andru [333]

Answer:

9.9 %

Explanation:

he formula for calculating dividend  yield is as follows,

Dividend yield= Annual dividend/stock price x 100

For this case: Annual dividend = 4 ( $ 2.1 per quarter)

     =$ 8.4

Stock price: $85

Dividend yield = $8.4/$85 x 100

       =9.88%

                                =9.9 %

6 0
2 years ago
Shirts.com makes business dress shirts. The shirts could have defects in various ways including in the weave or color of the fab
fredd [130]

Answer: c.) Yes, the process is in control.

Explanation:

For the process to be in control, the number of defects have to be between the Upper Control Limit and the Lower Control limits of the c-chart which can be used to measure defects of irregularities per unit.;

UCL = C-bar + z*√(c-bar)

LCL = C-bar - z*√(c-bar)

C - Bar = \frac{Number of Dfects}{Number of shirts}

C - Bar = \frac{4+6+3+1+5+6+4+6}{8}

C - Bar = 4.375

z = 3 when using the 3 sigma control

UCL = C-bar + z*√(c-bar)

UCL = 4.375 + 3 * √(4.375)

UCL = 10.65

LCL = C-bar - z*√(c-bar)

LCL = 4.375 - 3 * √(4.375)

LCL = -1.9

LCL = 0 (Lower limit minimum should be 0 at least)

Defects are within the control limits. The process is in control.

6 0
2 years ago
An appliance dealer must decide how many (if any) new microwave ovens to order for next month. The ovens cost $220 and sell for
Vlada [557]

Answer:

Explanation:

Order 0: we have unsold items for which the return is -25

return is -25*(.4*1+.2*2+.1*3) = -25*1.1 = $-27.50

Order 1: we have to sell at a discount if no orders, otherwise sell 1, and unsold items if demand 2 or 3

return is .3*(1/2*300-220) + (1-.3)*(300-220) + -.25*(.2*1+.1*2) = .3*-70+.7*80+-25*(.4) =

-21 + 56 - 10 = $25

Order 2: we have to sell at a discount if 0 or 1 orders, sell 1 or 2, and unsold items if demand 3

return is (.3*2+.4*1)*(1/2*300-220)+(.4*1+(.2+.1)*2)*(300-220)+-25*.1 =1*-70+1*80-25*.1 =

-70 + 80 - 2.5 = $7.50

Order 3:

return is (.3*3+.4*2+.2*1)*(1/2*300-220)+(.4*1+.2*2+.1*3)*(300-220) = 1.9*-70 + 1.1*80 =

-133 + 88 = -$45

Order 1, with a return of $25, as this is the highest return.

b) If we had a perfect information, we would never pay a penalty for underordering or suffer a discounted return from over-ordering

(.4*1+.2*2+.1*3)*(300-220) = 1.1*80 = $88

Then, the value of perfect information is $88 - $25 = $63

c) P(D=0|F) = P(F|D=0)*P(D=0)/(P(F|D=0)*P(D=0)+P(F|D=1)*P(D=1)+P(F|D=2)*P(D=2)+P(F|D=3)*P(D=3))=

.1*.3/(.1*.3+.2*.4+.3*.2+.9*.1)=.03/.26 = 3/26

P(D=1|F) = P(F|D=1)*P(D=1)/(P(F|D=0)*P(D=0)+P(F|D=1)*P(D=1)+P(F|D=2)*P(D=2)+P(F|D=3)*P(D=3))=

.2.4/(.1*.3+.2*.4+.3*.2+.9*.1)=.08/.26 = 4/13

P(D=2|F) = P(F|D=2)*P(D=2)/(P(F|D=0)*P(D=0)+P(F|D=1)*P(D=1)+P(F|D=2)*P(D=2)+P(F|D=3)*P(D=3))=

.3*.2/(.1*.3+.2*.4+.3*.2+.9*.1)=.06/.26 = 3/13

P(D=3|F) = P(F|D=3)*P(D=3)/(P(F|D=0)*P(D=0)+P(F|D=1)*P(D=1)+P(F|D=2)*P(D=2)+P(F|D=3)*P(D=3))=

.9*.1/(.1*.3+.2*.4+.3*.2+.9*.1)=.09/.26 = 9/26

P(D=0|U) = P(U|D=0)*P(0)/(P(U|D=0)*P(D=0)+P(U|D=1)*P(D=1)+P(U|D=2)*P(D=2)+P(U|D=3)*P(D=3))=

.8*.3/(.8*.3+.3*.4+.1*.2+.1*.1)=.24/.39 = 8/13

P(D=1|U) = P(U|D=1)*P(1)/(P(U|D=0)*P(D=0)+P(U|D=1)*P(D=1)+P(U|D=2)*P(D=2)+P(U|D=3)*P(D=3))=

.3*.4/(.8*.3+.3*.4+.1*.2+.1*.1)=.12/.39 = 4/13

P(D=2|U) = P(U|D=`)*P(`)/(P(U|D=0)*P(D=0)+P(U|D=1)*P(D=1)+P(U|D=2)*P(D=2)+P(U|D=3)*P(D=3))=

.1*.2/(.8*.3+.3*.4+.1*.2+.1*.1)=.02/.39 = 2/39

P(D=3|U) = P(U|D=3)*P(3)/(P(U|D=0)*P(D=0)+P(U|D=1)*P(D=1)+P(U|D=2)*P(D=2)+P(U|D=3)*P(D=3))=

.1*.1/(.8*.3+.3*.4+.1*.2+.1*.1)=.01/.39 = 1/39

P(N|D=0 = 1-.1-.8 = .1

P(N|D=1) = 1 - .2 - .3 = .5

P(N|D=2) = 1 - .3 - .1 = .6

P(N|D=3) = 1 - .9 - .1 = 0

P(D=0|N) = P(N|D=0)*P(D=0)/(P(N|D=0)*P(D=0)+P(N|D=1)*P(D=1)+P(N|D=2)*P(D=2)+P(N|D=3)*P(D=3))=.1*.3/(.1*.3+.5*.4+.6*.2+.0*.1)= .03/.35 = 3/35

P(D=1|N) = P(N|D=1)*P(D=0)/(P(N|D=0)*P(D=0)+P(N|D=1)*P(D=1)+P(N|D=2)*P(D=2)+P(N|D=3)*P(D=3))= .5*.4/(.1*.3+.5*.4+.6*.2+.0*.1)= .20/.35 = 4/7

P(D=2|N) = P(N|D=2)*P(D=2)/(P(N|D=0)*P(D=0)+P(N|D=1)*P(D=1)+P(N|D=2)*P(D=2)+P(N|D=3)*P(D=3))= .6*.2/(.1*.3+.5*.4+.6*.2+.0*.1)= .12/.35 = 12/35

P(D=3|N) = 0

If the result of the survey is an F, we have

P(D=0|F) = 3/26

P(D=1|F) = 4/13

P(D=2|F) = 3/13

P(D=3|F) = 9/26

If the order is 0, the return is -25*(1*4/13+2*3/13+3*9/26) = -25*47/26 = -1175/26 = -$45.19

If the order is 1, the return is 3/26*-70+(1-3/26)*80+-25*(1*3/13+2*9/26) = 515/13 = $39.62

If the order is 2, the return is (3/26*2+4/13)*-70+(1*4/13+2*(3/13+9/26))*80 + -25*9/26 =

1835/26 = $70.58

If the order is 3, the return is (3/26*3+4/13*2+3/13)*-70+(1*4/13+2*3/13+3*9/26)*80 =

795/13 = $61.15

We should order 2.

P(D=0|U) = 8/13

P(D=1|U) = 4/13

P(D=2|U) = 2/39

P(D=3|U) = 1/39

If we order 0, the return is (4/13*1+2/39*2+1/39*3)*-25 = -475/39 = -$12.18

If the order is 1, the return is 8/13*-70+(1-8/13)*80+-25*(1*2/39+2*1/39) =-580/39= -14.87

If the order is 2, the return is (8/13*2+4/13)*-70+(1*4/13+2*(2/39+1/39))*80 + -25*1/39 =

-2785/39= -$71.41

If the order is 3, the return is (8/13*3+4/13*2+2/39*1)*-70+(1*4/13+2*2/39+3*1/39)*80 =

-1780/13 = -$136.92

Order 0

P(D=0|N) = 3/35

P(D=1|N) = 4/7

P(D=2|N) = 12/35

P(D=3|N) = 0

If we order 0, the return is (4/7*1+12/35*2)*-25 = -220/7 = -$31.43

If the order is 1, the return is 3/35*-70+(1-3/35)*80+-25*(1*12/35) = 410/7 = $58.57

If the order is 2, the return is (3/35*2+4/7)*-70+(1*4/7+2*12/35)*80 = 340/7 = $48.57

We don't order 3, as the probability of 3 is 0

we order 1

We order 2 if there is an F, 0 if there is an N, and 1 if there is a U.

d) P(F) = .26

P(N) = .39

P(U) = .35

Then, the expected return is .26*1835/26 +-475/39*.39 + 410/7*.35 = $34.10

Since we make $25 if we just take 1, we should pay up to $34.10-$25 = $9.10 for the survey.

5 0
2 years ago
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