Answer:
the informal organization can hinder effective management.
Explanation:
Answer:
1.) neurilemma (option f)
2.) nissil bodies (chromatiophillic substance)
3.) neurofibrilis ( option g)
4.) myelin ( option e)
5.) dendrite ( option d)
6.) collateral ( option c)
7.) astrocytes (option a)
8.) axon ( option b)
9.) Unipolar neuron (option i)
Explanation:
The neurological terms described above are different parts of a nerve cell or neurones. The nerve cells are the basic Structural units of the nervous system. They are highly specialised for transmitting electric impulses. They can also be grouped according to the number of processes they possess, for example, the UNIPOLAR NEURONS( those with one process only). Each neuron, however, is composed of the same basic parts which include:
--> The CELL BODY: they may be angular or oval in shape with a large nucleus and dense granulated cytoplasm. In the cytoplasm, rough Endoplasmic reticulum which contains CHROMATIOPHILLIC SUBSTANCE (nissil bodies) and Golgi apparatus are also seen.Network of threadlike structures known as neurofibrilis are also seen within the cell body and extending into axon.
--> DENDRONS: these are one or more extensions which branches to form many fine dendrites. The DENDRONS carry nerve impulses( action potential) that their dendrites receive to the cell body.
--> AXON: this is a long process which branches at it's free end to end in synaptic knobs. It carries electric impulses away from the cell body. Most times, a substance of Schwann cell known as MYELIN SHEATH which is composed of lipoprotein insulates axons and increases impulse speed.
The nurse should assess the patient vital sign and notify the healthcare provider. For 2.5 hour after neck dissection, production of 40ml by the drainage is a bit excessive. There might be a bleeding in the site of operation that becomes the source of the drainage. Change dressing will not do anything. Applying pressure can be done if the site of bleeding is known.
Answer: The estimated population is 1250 mice
Explanation: The method use was marked and recapture, in which individuals are marked in the first capture and after some time biologist trap a new group of individuals that can be or not marked
Whit this data is possible to estimate the size of a population applying the Peterson method but is important to make some considerations such as:
1. All indivuals have the same probability to be capture
2, The population remain constant in terms of birth and death rate.
Taking this into account, the formula that allows to determine the size of the population is:
N=CM / R
where N is the size of the population, C is number of indivuals trapped in recapture, M is number of individuals marked in the first capture and R is the number of marked animals trapped in recapture
In this case:
N = 250 * 200 / 40 = 1250
Answer:
0.05 mg/mL ( B )
Explanation:
Given data:
20 mg/ml starch
2% solution = 2g of solute is in 100g of solvent
<u>Determine the new concentration in mg/ml </u>
Dilution equation = C1V1 = C2V2
new concentration ; applying the dilution factor
dilution factor = 1 : 400 ; ( 2 /400 )g = 0.005 g of solute is present in every 100 mL
∴ new concentration = 0.00005 g / 1 mL * ( 1000 mg / 1g ) = 0.05 mg/mL