Answer:
Genotypic and Phenotypic ratios → 1:1:1:1
- 25% of the progeny is expected to be SsWw, exhibiting spotted skin and wooly hair, SsWw
- 25% of the progeny is expected to be Ssww, exhibiting spotted skin and non-wooly hair, Ssww
- 25% of the progeny is expected to be ssWw, exhibiting non- spotted skin and wooly hair, ssWw
- 25% of the progeny is expected to be ssww, exhibiting non-spotted skin and non-wooly hair, ssww
Explanation:
<u>Available data</u>:
- spotted skin (S) is dominant over non-spotted skin (s)
- wooly hair (W) is dominant over non-wooly hair (w)
- Cross: heterozygous spotted, non-wooly mammoth with a heterozygous wooly-haired, non-spotted mammoth.
Parentals) Ssww x ssWw
Gametes) Sw, Sw, sw, sw
sW, sW, sw, sw
Punnett square) Sw Sw sw sw
sW SsWw SsWw ssWw ssWw
sW SsWw SsWw ssWw ssWw
sw Ssww Ssww ssww ssww
sw Ssww Ssww ssww ssww
F1) 4/16 = 1/4 = 25% of the progeny is expected to be SsWw, exhibiting spotted skin and wooly hair
4/16 = 1/4 = 25% of the progeny is expected to be Ssww, exhibiting spotted skin and non-wooly hair
4/16 = 1/4 = 25% of the progeny is expected to be ssWw, exhibiting non- spotted skin and wooly hair
4/16 = 1/4 = 25% of the progeny is expected to be ssww, exhibiting non-spotted skin and non-wooly hair.
Genotypic and Phenotypic ratios → 1:1:1:1
Cellular respiration is a metabolic process that converts glucose and utilizes oxygen to generate the energy needed to carry out system processes, specifically ATP. The by-products produced from the process includes water and carbon dioxide.
glucose-reactant;co2 & water-products
Plants that have increased levels of mutations
that can either be in their
germ-line or somatic tissues is what the plant breeder should look for because if
plants re defective in DNA <span>repair they should have
higher rates of mutation .</span>
<span />
<span>
</span>
The answer to the question is the cleavage furrow of eukaryotic animal cells. Analogous structures are various structures in different species having the same function but evolved separately, thus do not share a common ancestor. FtsZ assembles into a ring at the future site of the septum of bacterial division, it is a prokaryotic homologue to the eukaryotic protein tubulin.
