Question

On a coordinate plane, 2 lines are shown. The first solid straight line has an equation of y greater-than-or-equal-to negative one-fifth x + 1, has a negative slope, and goes through (negative 5, 2) and (0, 1). Everything above the line is shaded. The second dashed solid line has equation y less-than 2 x + 1, has a positive slope, and goes through (negative 2, negative 3) and (0, 1). Everything to the right of the line is shaded. Which ordered pairs make both inequalities true? Check all that apply. (–2, 2) (0, 0) (1,1) (1, 3) (2, 2)

Answer 1

Answer:

(-2,2) (1,1) (2,2)

Step-by-step explanation:

the following ordered pair (-2,2) (1,1) (2,2) makes both inequalities true because they are located in the region that staisfies both inequalities.

The pair (0,0) does not satisfy because it is at the origin and not inclusive in the shaded region

And the ordered pair (1,3) means when x =1 , y = 3; where y =3 falls on the line of the inequality y less than 2x+1 and the line is a dashed solid line supported with fact that it is strictly less than, hence makes the ordered pair fall out of the region.

Answer 2

Answer:

its C and E

Step-by-step explanation: