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erica [24]
2 years ago
4

A canned food manufacturer has its manufacturing plants in three locations across a state. Their product has to be transported t

o 3 central distribution centers, which in turn disperse the goods to 72 stores across the state. Which of the following is most likely to be the objective function in this scenario?a. A time-series plot
b. A network graph
c. A scatter chart
d. A contour plot
Mathematics
1 answer:
omeli [17]2 years ago
3 0
C i had this one your welcome
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A refund of $3.15 on a $8.64 bill
Varvara68 [4.7K]

8.64 - 3.15 = $5.49 if this is what you are asking

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2 years ago
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You have just opened a new dance club, Swing Haven, but are unsure of how high to set the cover charge (entrance fee). One week
aliya0001 [1]

Answer:

q = -6p + 104

Step-by-step explanation:

Linear function:

A linear function has the following format:

q = mp + b

In which m is the slope and b is the q-intercept.

One week you charged $4 per guest and averaged 80 guests per night. The next week you charged $10 per guest and averaged 44 guests per night.

This means that we have these following points: (4,80), (10,44).

Finding the slope:

With a pair of points, the slope is given by the change in q divided by the change in p.

Change in q: 44 - 80 = -36

Change in p: 10 - 4 = 6

Slope: m = \frac{-36}{6} = -6

So

q = -6p + b

Finding b:

We replace one of the points. Replacing (4,80).

q = -6p + b

80 = -6*4 + b

b = 104

So

q = -6p + 104

7 0
2 years ago
Let $f(x) = x^{10}-8x^8-8x^3+12x^2-5x-5$. Without using long division (which would be horribly nasty!), find the remainder when
valentina_108 [34]

Solution:

f(x) = x^{10}-8x^8-8x^3+12x^2-5x-5

We have to find the remainder when f(x) is divided by x^2-1.

x²-1=0

x=\pm1

f(1)=1^{10}-8(1)^8-8(1)^3+12(1)^2-5(1)-5=1-8-8+12-5-5=1-16+12-10=13-26=-13\\\\f(-1)=(-1)^{10}-8(-1)^8-8(-1)^3+12(-1)^2-5(-1)-5=1-8+8+12+5-5=1+12=13

So, remainder is 13 and -13.

5 0
2 years ago
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Twenty-five juniors from a University volunteer to allow their Math GRE test scores to be used in a study. These 25 juniors had
fgiga [73]
Let's start first by writing down the given:
σ = 100
sample mean = 450
sample size = 25

These information, plus the fact that we know that the population is approximately normally distributed, would tell us that we can use the normal distribution curve in analyzing the problem.

A confidence interval of the mean is just a range statistically estimated to contain the population mean. For a 90% confidence interval, we would look at the Z-table and see where 90% of the data falls. We'll notice that it will fall within 1.645 standard deviations of the mean.

Next, we look for the standard error of the mean. This will have a formula
error= \frac{standard deviation of population}{ \sqrt{N} }

The standard error would just therefore be equal to
\frac{100}{ \sqrt{25} }= \frac{100}{5}  =20

Lastly, we just get the product of the standard error and 1.645 and add it to 450 for the maximum value and subtract it to 450 for the minimum value.
450-20(1.645)=417.1
450+20(1.645)=482.9

ANSWER: 417.1<μ<482.9

8 0
2 years ago
Marie spends $450.00 at a department store. She has two coupons: one for a 15% discount and one for $50 off any purchase above $
VMariaS [17]

Answer:

Her first coupon ti be used is $50 off a purchase above $300

Final purchase price= $340

Step-by-step explanation:

Marie has two coupons

one for a 15% discount and one for $50 off any purchase above $300.

The stores allow the two coupons to be combined and she spends a total of $450.

Her first coupon ti be used is $50 off a purchase above $300.

So Marie have $400 now

15% off $400= 400-(0.15*400)

15% off $400 = 400-60

15% off $400 =$ 340

6 0
2 years ago
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