1. multiply 250 by 10% (250 * .1= 25)
2. Then subtract 25 from 250 (250 -25= 225)
2. Then multiply 225 by 16% (225 * .16 = 36)
3. Add 225 + 36 = 261.
4. 261 is your final answer
<span>Using the Pythagorean theorum we can solve this v a^2+b^2= c^2. A is the distance from base of house to ladder A= 1.5, c ifls length of ladder, c= 10. (1.5)^2 + ;b^2 = (10)^2. Solve for b. B= 9.88. 12 foot height of house - 9.88 feet to top of angled ladder = 2.11 from top of ladder to edge of roof</span>
Answer=1/24
1/3+5/8=
to solve for this, we need the denominators of the fractions to match.
The LCM of 3 and 8 is 24
1/3=8/24
5/8=15/24
8/24+15/24=23/24
Now if we're using 23/24, then only 1/24 is left.
24/24-23/24=1/24
Hello,
a) | |PA|-π |>| |PB|-π | (see pic)
c) 3.14< x/113 <=π <22/7
==>3.14*113<x<22/7 * 113
==>354.82 <x < 355.14285
==>x=355
Answer 355/113=3,1415929203539823008849557522124
The answer is 141.35 ft²
Before the first break, it was painted:
150 ft² ÷ 2 = 75 ft²
Now it's left:
150 ft² - 75 ft² = 75 <span>ft²
Before the second break, it was painted:
75 </span>ft² ÷ 2 = 37.5 <span>ft²
Now it's left:
75 </span>ft² - 37.5 ft² = 37.5 <span>ft²
Before the third break, it was painted:
37.5 </span>ft² ÷ 2 = 18.75 <span>ft²
</span><span>Now it's left:
</span>37.5 ft² - 18.75 ft² = 18.75 <span>ft²
</span>
<span>Before the fourth break, it was painted:
</span>18.75 ft² ÷ 2 = 9.375 <span>ft²
</span><span>Now it's left:
</span>18.75 ft² - 9.375 ft² = 9.375 <span>ft²
</span>
<span>Before the fourth break, it was painted:
</span>9.375 ft² ÷ 2 = 4.6875 <span>ft²
</span><span>Now it's left:
</span>9.375 ft² - 4.6875 ft² = 4.6875 ft²
Now, we will sum what he painted for now:
75 ft² + 37.5 ft² + 18.75 ft² + 9.375 ft² 4.6875 ft² = 141.3125 ft² ≈ 141.35 ft²
When the painter takes his fifth break, there will be <span>141.35 ft² of the wall painted.</span>
