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Lesechka [4]
2 years ago
14

A fishing club on the Restigouche River in Canada kept detailed records on the numbers of fish caught by its members between 188

0 and 1930. Average catch tends to be cyclic each decade with the average minimum catch of 0.9 salmon per day occurring in years ending with O an average maximum catch of ʼ salmon per day occurring in years ending with 5.t (Note: This exercise corresponds to the subsection Characteristics of a Sine Function and requires use of the formulas for average value, amplitude, period, and horizontal shift to construct sine models rather than curve-fitting using technology.) (a) Calculate the period and horizontal shift of the salmon catch cycle. Use these values to calculate the parameters b and c for a model of the form rx) = a sin(bx + c) + d, where x = 0 corresponds to the year 1880. (Round your answers to three decimal places.)
(b) Calculate the amplitude and average value of the salmon catch cycle amplitude average value salmon per day salmon per day (c) Use the constants from parts (a) and (b) to construct a sine model for the average daily salmon catch. (Round all numerical values to three decimal places.)
Mathematics
1 answer:
MrMuchimi2 years ago
4 0

Answer:a

Step-by-step explanation:

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What input value produces the same output value for the two functions on the graph ?
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we know that

The intersection point of both graphs is a common point for both functions, for which for the same input value, both functions will have the same output value.

so

the point of intersection is (4,3)

for an input value equal to 4

the output value for both functions is 3

therefore

<u>the answer is the option</u>

X= 4

4 0
2 years ago
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categorize the graph as linear increasing, linear decreasing, exponential growth, or exponential decay.
soldier1979 [14.2K]
It is exponential growth
5 0
2 years ago
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Solve the trigonometric equation in the interval [0, 2π). Give the exact value, if possible; otherwise, round your answer to two
svp [43]

Answer:

θ∈{\frac{\pi }{8},\frac{5\pi }{8},\frac{9\pi }{8},\frac{13\pi }{8}}

Explanation:

The given equation is

sin(2\theta )-cos(2\theta )=0

\Rightarrow sin(2\theta )=cos(2\theta )\\\\\therefore \frac{sin(2\theta )}{cos(2\theta )}=1\\\\tan(2\theta )=1\\\\\therefore 2\theta =n\pi +\frac{\pi}{4}\\\\\therefore \theta =\frac{n\pi }{2}+\frac{\pi }{8}

Applying values on 'n' we obtain values of θ that beling to [0,2π)

For n=0, θ=\frac{\pi }{8}

For n=1, θ =\frac{5\pi }{8}

For n=2,θ =\frac{9\pi }{8}

For n=3,θ =\frac{13\pi }{8}

6 0
2 years ago
A company has 125 personal computers. The probability that any one of them will require repair on a given day is 0.15.
mariarad [96]

Answer:

a. the probability that any one of the computers will require repair on a given day is constant

Step-by-step explanation:

The following properties must be true in order for a distribution to be binomial:

- A fixed number of trials (125 computers)

- Each trial is independent of the others (one computer requiring repair does not interfere with the likelihood of another requiring repair).

There are only two outcomes (requires repair or do not require repair)

The probability of each outcome remains constant from trial to trial (All computers have the same likelihood of requiring repair, 0.15).

Therefore, the alternative that better fits those properties is alternative a. the probability that any one of the computers will require repair on a given day is constant

8 0
2 years ago
Eve’s teacher asked her to graph the function y=-cot(x)-1 by reflecting the graph of the function y=cot(x) about the x-axis and
Ronch [10]

Answer:

The correct answer is A: Yes, it matters. The graph of a function y = cot(x) should be reflected about the x-axis before it is translated 1 unit up.

Step-by-step explanation:

The reason being is that when there are two factors that affect a graph's verticality, order does matter. Here is the exact reasoning:

Say you translated 1 unit down first. You would then have y = cot(x) - 1. Then, in order to reflect it about the x axis, you must multiply the entire right side of the equation by negative 1. So now you have y = -1(cot(x) -1), which, when distributed, gives you: y = -cot(x) + 1, instead of y = -cot(x) -1. Therefore, you must reflect before you translate.

And you may be wondering, why then, isn't D correct? Since, you could fix that by translating up 1 and then reflecting, so that you get the final product. Well, it specifies that it can be done in any order. So one way you could get the equation you want, but the other way, you get y = -cot(x) + 1, which, again, is incorrect.

I hope this cleared it up for you!

5 0
2 years ago
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