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Nuetrik [128]
2 years ago
15

Killer whales are known to reach 32 ft in length and have a mass of over 8,000 kg. They are also very quick, able to accelerate

up to 30 mi/h in a matter of seconds. Disregarding the considerable drag force of the water, calculate the average power a killer whale named Shamu with mass 8.00 x 103 kg would need to generate to reach a speed of 12 m/s in 6 s
Physics
1 answer:
Ratling [72]2 years ago
4 0

Answer:

Power, P = 96 kW

Explanation:

Mass of Shamu, m = 8000 kg

Initial velocity, u = 0

Final velocity, v = 12 m/s

We need to find the average power of the whale. It is equal to the work done per unit time. Work done is equal to the change in kinetic energy. So,

P=\dfrac{\Delta K}{t}\\\\P=\dfrac{mv^2}{2t}\\\\P=\dfrac{8000\times 12^2}{2\times 6}\\\\P=96000\ W

or

P = 96 kW

So, the average power of the killer whale is 96 kW.

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Help asap please!! An aluminum block of mass 12.00 kg is heated from 20 C to 118 C. If the specific heat of aluminum is 913 J-1
professor190 [17]
Q = mCΔT, where Q = Amount of energy required, m = mass of the blcok, C = specific heat, ΔT = change in temperature.

Using the given values;

Q = 12*913*(118-20) = 1073688 J = 1073.688 kJ.

The correct answer in B.
7 0
2 years ago
A student measured the density of Galena to be 7.9g/cm3 however the known density of Galena is 7.6g/cm3 . Calculate the percent
VLD [36.1K]
7.9/7.6-1=3.9%
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You perform nine (identical) measurements of the acceleration of gravity (units of m/s2): 10.1,9.87, 9.76, 9.91, 9.75, 9.88, 9.6
AveGali [126]

Answer:

0.01

Explanation:

Given the data:

10.1,9.87, 9.76, 9.91, 9.75, 9.88, 9.69, 9.83, 9.90

True value = 9.81

Mean value :

Σx / n

Sample size, n = 9

(10.1 + 9.87 + 9.76 + 9.91 + 9.75 + 9.88 + 9.69 + 9.83 + 9.90) / 9

= 88.69 / 9

= 9.854

Standard deviation (σ) :

Sqrt (Σ(X - m)² / n)

[(10.1 - 9.854)^2 + (9.87 - 9.854)^2 + (9.76 - 9.854)^2 + (9.91 - 9.854)^2 + (9.75 - 9.854)^2 + (9.88 - 9.854)^2 + (9.69 - 9.854)^2 + (9.83 - 9.854)^2 + (9.90 - 9.854)^2] / 9

Sqrt(0.113824 / 9)

Sqrt(0.0126471)

σ = 0.1124593

Standard Error = σ / sqrt(n)

Standard Error = 0.1124593 / 9

Standard Error = 0.0124954

Standard Error = 0.01 ( 1 significant digit)

3 0
2 years ago
Explain how climbing a mountain is similar to hiking from the equator to one of the poles
Igoryamba

Explanation:

  • Climbing a mountain is similar to hiking from the equator to the pole because in both cases temperature decreases.
  • The higher you go, the cooler it becomes.
  • For a certain elevation, there is particular drop in temperature. High altitudes offers cooler temperatures.
  • The equator receives a huge insolation and the sun is overhead there.
  • It implies that the temperature is always high around the equatorial region.
  • As one increases latitude, the temperature drops and its is coldest at the pole.
  • In both cases, temperature drops and it gets colder.

Learn more:

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8 0
2 years ago
A girl launches a toy rocket from the ground. The engine experiences an average thrust of 5.26 N. The mass of the engine plus fu
Triss [41]

Answer: The answer for A is - v = 786.93 m/s

The answer for B is - v = 122.40 m/s

Explanation:

a) To find the average exhaust speed (v) of the engine we can use the following equation:

F = vΔm

Where:

F: is the thrust by the engine = 5.26 N

Δm: is the mass of the fuel = 12.7 g

Δt: is the time of the burning of fuel = 1.90 s

v = F×ΔT/ΔT

b) To calculate the final velocity of the rocket we need to find the acceleration.

The acceleration (a) can be calculated as follows:

a = F/M

In the above equation, m is an average between the mass of the engine plus the rocket case mass and the mass of the engine plus the rocket case minus the fuel mass:

m = (m_{engine} + m_{rocket}) + (m_{engine} + m_{rocket} - m_{fuel})}{2} = {2*m_{engine} + 2*m_{rocket} - m_{fuel}}{2} = 2*25.0 g + 2*63.0 g - 12.7 g}{2} = 81.65 g

Now, the acceleration is:

a = 5.26 N/81.65-t 10^³kg} = 64.42 m*s^²

Finally, the final velocity of the rocket can be calculated using the following kinematic equation:

v= v_{0} + at = 0 + 64.42 m*s^{-2}*1.90 s = 122.40 m/s

7 0
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