Answer:
e) Code segment II produces correct output for all values of str, but code segment I produces correct output only for values of str that contain "pea" but not "pear".
Explanation:
<em>if - elseif - else statements work in sequence in which they are written. </em>
- <em> </em>In case <em>if() statement is true, </em>else if() and else statements will not get executed.
- In case <em>else if() statement is true</em>, conditions in if() and else if() will be checked and else statement will not be executed.
- In case <em>if() and else if() both are false</em>, else statement will be executed<em>.</em>
First, let us consider code segment I.
In this, first of all "pea" is checked in if() statement which will look for "pea" only in the String str. So, even if "pearl" or "pear" or "pea" is present in 'str' the result will be true and "pea" will get printed always.
After that there are else if() and else statements which will not get executed because if() statement was already true. As a result else if() and else statements will be skipped.
Now, let us consider code segment II.
In this, "pearl" is checked in if() condition, so it will result in desired output.
Executable code is attached hereby.
Correct option is (e).
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Answer:
To check if the year comes under each 100th year, lets check if the remainder when dividing with 100 is 0 or not.
Similarly check for 400th year and multiple 0f 4. The following C program describes the function.
#include<stdio.h>
#include<stdbool.h>
bool is_leap_year(int year);
void main()
{
int y;
bool b;
printf("Enter the year in yyyy format: e.g. 1999 \n");
scanf("%d", &y); // taking the input year in yyyy format.
b= is_leap_year(y); //calling the function and returning the output to b
if(b==true)
{
printf("Thae given year is a leap year \n");
}
else
{
printf("The given year is not a leap year \n");
}
}
bool is_leap_year(int year)
{
if(year%100==0) //every 100th year
{
if(year%400==0) //every 400th year
{
return true;
}
else
{
return false;
}
}
if(year%4==0) //is a multiple of 4
{
return true;
}
else
{
return false;
}
}
Explanation:
Output is given as image
Answer:
Big Oh notation is used to asymptotically bound the growth of running time above and below the constant factor.
Big Oh notation is used to describe time complexity, execution time of an algorithm.
Big Oh describes the worst case to describe time complexity.
For the equation; T(N) = 10000*N + 0.00001*N^3.
To calculate first of all discard all th constants.
And therefore; worst case is the O(N^3).
Answer:
It is definitely not used for locating the options in the menu. its the new feature available which is available from the Tell Me text box which you can find immediately right of the very last cmd tab which is above the ribbon. And as you add any help topic to this into textbox, the excel shows all Excel command list , command which are related to the help topic in a drop down.
Explanation:
The answer is self explanatory.
