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vesna_86 [32]
2 years ago
4

You drop a ball from a stair case that is 36 ft high. By the time you get down the stairs to measure the height of the bounce, t

he ball has bounced four times and has a height of 2.25 ft after its fourth bounce. How high did the ball bounce after it first hit the floor?
Mathematics
1 answer:
Reika [66]2 years ago
5 0

Answer:

18 feet

Step-by-step explanation:

After each bounce, the ball reaches only a percentage of the maximum height it reached before.

The first height is 36 feet, after the first bounce, it will be 36*r, where r is the ratio of the height the ball can still reach by the previous maximum height.

In the second bounce, the height is 36*r^2

In the third bounce, the height is 36*r^3

In the fourth bounce, the height is 36*r^4, and this value is 2.25 ft, so:

36*r^4 = 2.25

r^4 = 2.25/36

r^4 =  0.0625

r = 0.5

So, after the first bounce, the height is:

36*r = 36*0.5 = 18 feet

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vector u is represented by the directed line segment RS and vector v is represented by the directed line segment OP. if R=(8,-2)
melamori03 [73]

The given points are

R=(8,-2) , S=(11,-6), O=(-3,-9), and P=(0,-13)

To find the value of u and v, we have to perform subtraction of the points . That is

u= RS = =

v = OP =  =

Since we get the same values of u and v , therefore the two vectors are equal .

8 0
2 years ago
Geoffrey is evaluating the expression StartFraction (negative 3) cubed (2 Superscript 6 Baseline) Over (Negative 3) Superscript
makkiz [27]

The mathematical expression does not seem clear but I have made an attempt to make sense of what is implied.

Answer:

<em>a</em> = 4, <em>b</em> = 2, <em>c</em> = 16, <em>d</em> = 9

Step-by-step explanation:

\dfrac{(-3)^3(2^6)}{(-3)^5(2^2)} = \dfrac{(2)^a}{(-3)^b} = \dfrac{c}{d}

Solving the first part of the question by indices,

\dfrac{(-3)^3(2^6)}{(-3)^5(2^2)} = (-3)^{3-5}(2)^{6-2} = (-3)^{-2}(2)^{4} = \dfrac{(2)^4}{(-3)^2}

Comparing the rightmost term with the second term in the question,

<em>a</em> = 4, <em>b</em> = 2

Solving on,

\dfrac{(2)^4}{(-3)^2} = \dfrac{(2)\times(2)\times(2)\times(2)}{(-3)\times(-3)} = \dfrac{16}{9}

Comparing with the final term in the question,

<em>c</em> = 16 and <em>d</em> = 9

Therefore,

<em>a</em> = 4, <em>b</em> = 2, <em>c</em> = 16, <em>d</em> = 9

3 0
2 years ago
Read 2 more answers
Brody has his computer repaired at store A. His bill was:
PIT_PIT [208]

Initial repair cost = $1200

Gratuity = 15% of the initial repair cost

= 15% of 1200

=\frac{15}{100} (1200)

= 15 × 12

= 180

Hence, the gratuity for the service is $180.

4 0
2 years ago
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A textbook store sold a combined total 402 of psychology and math textbooks in a week. The number of psychology textbooks sold w
uranmaximum [27]

Answer:

The number of textbooks of each type were sold is <u>134 math </u>and <u>268 psychology </u>books.

Step-by-step explanation:

Given:

Total number of math and psychology textbooks sold in a week is 402.

Now, let the number of math textbooks sold be x.

And, the number of psychology textbooks be 2x.

According to question:

x+2x=402

3x=402

Dividing both sides by 3 we get:

x=134

So, total number of math textbooks were 134 .

And, total number of psychology textbooks were 2x=2\times 134

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Therefore, the number of textbooks of each type were sold is 134 math and 268 psychology books.

4 0
2 years ago
A particle moves on the circle x2+y2=25 in the xy-plane for time t≥0. At the time when the particle is at the point (3,4), dx/dt
yaroslaw [1]

Answer:

\displaystyle y'=-\frac{9}{2}

Step-by-step explanation:

<u>Differentiation</u>

We have a relationship between x and y as follows:

x^2+y^2=25

Both variables depend on time t for t≥0.

Differentiating with respect to time:

(x^2)'+(y^2)'=(25)'

Applying the derivative of a power function:

2xx'+2yy'=0

Recall the derivative of a constant is 0.

Dividing by 2:

xx'+yy'=0

Solving for y':

\displaystyle y'=-\frac{xx'}{y}

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\displaystyle y'=-\frac{3\cdot 6}{4}

Operating:

\displaystyle y'=-\frac{18}{4}

Simplifying:

\mathbf{\displaystyle y'=-\frac{9}{2}}

8 0
2 years ago
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