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Romashka [77]
1 year ago
6

Jerry has an insurance policy with a premium of $150 per month. In June, he’s in an accident and receives a bill with a total co

st of $6000. His deductible is $1500, and his coverage limit is $4000. How much does Jerry owe in June?
Business
1 answer:
I am Lyosha [343]1 year ago
4 0

Answer:

Amount Jerry owe in June = $2,650

Explanation:

Given:

Premium per month = $150

Total cost (Accident) = $6,000

Deductible amount = $1,500

Coverage limit = $4000

Amount Jerry owe in June = ?

Computation of amount Jerry owe :

Amount Jerry owe in June = Coverage limit - Deductible amount + Premium per month

Amount Jerry owe in June = $4,000 - $1,500 + $150

Amount Jerry owe in June = $2,500 + $150

Amount Jerry owe in June = $2,650

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Answer:

8,200

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You have to email the list of 5000 names first and then you have also second list for emailing consists of 3900 names. The sum of both the list is equal to 8,900. But there are 700 names which are common on both lists. You have to subtract 700 from 8,900 to identify the number of unique names you have. The answer you will get after subtraction is 8,200.

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Which of the following is an example of shadowing? Select one: a. Two new recruits working on an automobile’s rear axle b. Three
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Answer:<em> Option (b) is correct.</em>

From the given options , the following is an example of shadowing:<em> Three young interns practicing under the guidance of an experienced surgeon. </em>

<em>Shadowing here refers to on-the-job learning program. It also includes development program related to career and leadership. This also involves working with individuals who might have different work, or might have to teach the individual about aspects related to the work, business or competencies. </em>

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1 year ago
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Sarah just completed her 1040EZ tax return form and double-checked it. Now she should _____.
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2 years ago
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Larry Ellison starts a company that manufactures high-end custom leather bags. He hires two employees. Each employee only begins
HACTEHA [7]

Answer:

12.55 days

Explanation:

<em><u>Provided information </u></em>

Number of employees 2

Average production time=1.8 days

Standard deviation=2.7 days

Inter-arrival time= 1 day

Coefficient of variation= 1 day

Standard deviation of inter-arrival time= 1 day

The coefficient of variations

<u>Inter-arrival coefficient of variation </u>

C_{vi}=\frac {\sigma}{T} where \sigma is standard deviation of inter-arrival time, T is inter-arrival time and C_v is coefficient of variation of inter-arrival time

C_{vi}=\frac {1 day}{1 day}=1

<u>Production time coefficient of variation </u>

C_{vp}=\frac {2.7}{1.8}=1.5

<u><em>Total utilization time </em></u>

U=\frac {T}{n*T_i} where T is the time of production, n is number of employees, U is utilization, T_i is inter-arrival time

U=\frac {1.8}{2*1}=0.9

Therefore, utilization time by 2 employees is 0.9

<u>Expected average waiting time </u>

T_e=(\frac {T}{n*T_i})*0.5(C_{vi}^{2}+C_{vp}^{2})*(\frac{U^{\sqrt{2(n+1)}-1}}{1-U})

Where T_e is expected average waiting time and the other symbols as already defined

Substituting 1.5 for C_{vp}, 1 for C_{vi}, 0.9 for U, 2 for n, 1 for T_iand 1.8 for T

T_e=(\frac {1.8}{2*1})*0.5(1^{2}+1.5^{2})*(\frac{0.9^{\sqrt{2(2+1)}-1}}{1-0.9})

T_e=0.9*1.625*8.583709=12.55367 days  and rounding off to 2 decimal places we obtain 12.55 days

Therefore, expected duration between order received and beginning of production is approximately 12.55 days

4 0
1 year ago
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