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tensa zangetsu [6.8K]

1 year ago

10

Circle O is shown. Line segments A O and B O are radii. A line is drawn from point A to point D to form a chord. Another line is

drawn from point B to point D to form a chord. The measure of arc B D is 98 degrees. The measure of arc A D is 212 degrees. The measure of arc AB is °. The measure of angle AOB is °. The measure of angle BDA is °.
*I FOUND THE ANSWERS*
AB= 50°
AOB= 50°
BDA=25°

2 answers:

Artist 52 [7]1 year ago

6 0

Answer:

yes you are correct

Step-by-step explanation

the answers to your question are correct it is:

1) 50 degrees

2) 50 degrees

3) 25 degrees

AleksAgata [21]1 year ago

6 0

That is Correct ^^^^

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Answer:

1/128 kilograms.

Step-by-step explanation:

First, multiply 16 and 4 to get 64. Since the weight of the box is 1/2 (or 0.5), so we have each cookie's weight at 1/128. Please mark this "brainliest" (the crown) if you like this answer!

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1 year ago

I WILL AWARD BRAINLIEST!! PLEASE HELP!!

bezimeni [28]

Answer:

Part 1) $A(57/7,9),B(4,16/5), m=7/5$

Part 2) $A(-7,6),B(9,-6/7), m=-3/7$

Part 3) $A(80/3,9),B(5,2.5), m=0.3$

Part 4) $A(-10/63,1/3),B(2/3,-22/90), m=-0.7$

Part 5) $A(-1/5,7),B(8,48), m=5$

Step-by-step explanation:

we know that

The equation of the line into slope intercept form is equal to

$y=mx+b$

where

m is the slope

b is the y-coordinate of the y-intercept

Part 1) we have

$7x-5y=12$

step 1

Find the slope

$7x-5y=12$

isolate the variable y

$y=(7/5)x-(12/5)$

so

the slope is $m=(7/5)$

step 2

Find the missing coordinate of point A

To find the x-coordinate of point A substitute the value of y-coordinate in the equation

$9=(7/5)x-(12/5)$

$(7/5)x=9+(12/5)$

$(7/5)x=(57/5)$

$x=(57/7)$

step 3

Find the missing coordinate of point B

To find the y-coordinate of point B substitute the value of x-coordinate in the equation

$y=(7/5)(4)-(12/5)$

$y=(28/5)-(12/5)$

$y=(16/5)$

Part 2) we have

$y=-(3/7)x+3$

step 1

Find the slope

the slope is $m=-(3/7)$

step 2

Find the missing coordinate of point A

To find the x-coordinate of point A substitute the value of y-coordinate in the equation

$6=-(3/7)x+3$

$(3/7)x=3-6$

$(3/7)x=-3$

$x=-7$

step 3

Find the missing coordinate of point B

To find the y-coordinate of point B substitute the value of x-coordinate in the equation

$y=-(3/7)(9)+3$

$y=-(27/7)+3$

$y=-(6/7)$

Part 3) we have

$y=0.3x+1$

step 1

Find the slope

the slope is $m=0.3$

step 2

Find the missing coordinate of point A

To find the x-coordinate of point A substitute the value of y-coordinate in the equation

$9=0.3x+1$

$0.3x=9-1$

$0.3x=8$

$x=80/3$

step 3

Find the missing coordinate of point B

To find the y-coordinate of point B substitute the value of x-coordinate in the equation

$y=0.3(5)+1$

$y=2.5$

Part 4) we have

$6.3x+9y=2$

step 1

Find the slope

$6.3x+9y=2$

isolate the variable y

$y=-(0.7)x+(2/9)$

so

the slope is $m=-0.7$

step 2

Find the missing coordinate of point A

To find the x-coordinate of point A substitute the value of y-coordinate in the equation

$(1/3)=-(0.7)x+(2/9)$

$(0.7)x=(2/9)-(1/3)$

$(0.7)x=(2/9)-(1/3)$

$(0.7)x=-(1/9)$

$x=-(10/63)$

step 3

Find the missing coordinate of point B

To find the y-coordinate of point B substitute the value of x-coordinate in the equation

$y=-(0.7)(2/3)+(2/9)$

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Part 5) we have

$y-5x=8$

step 1

Find the slope

$y-5x=8$ -------> $y=5x+8$

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step 2

Find the missing coordinate of point A

To find the x-coordinate of point A substitute the value of y-coordinate in the equation

$7=5x+8$

$5x=7-8$

$x=-1/5$

step 3

Find the missing coordinate of point B

To find the y-coordinate of point B substitute the value of x-coordinate in the equation

$y=5(8)+8$

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To find our quotient we are going to perform long division.

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Notice that even tough our polynomial is written in descending form, $x^3$ is missing, so we are going to use $0x^3$ to fill the gap:

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In our case the first term of the dividend is $3x^4$ and the first term of the divisor is $x$ , so $\frac{3x^4}{x} =3x^3$ . Notice that $3x^3$ is the first term of the quotient.

Step 3. Multiply the first term of the quotient by the terms of the divisor and subtract them from the respective term of the dividend.

The first term of our quotient (from the previous step) is $3x^3$ and the divisor is $(x-1)$ , so $3x^3(x-2)=3x^4-6x^3$ . Now, we are going to subtract them from the respective term (the term with the same power) of the dividend. The respective terms of the dividend are $3x^4$ and $0x^3$ , so $3x^4-3x^4=0$ and $0x^3-(-6x^3)=0x^3+6x^3=6x^3$

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After finish the process (check the attached picture), we can conclude that the quotient of $3x^4-4x^2+8x-1$ ÷ $(x-2)$ is $3x^3+6x^2+8x+24$ with a remainder of $47$ , or in a different notation: $3x^3+6x^2+8x+24+\frac{47}{x-2}$

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