Let D be dogs and C be cats
<em>dogs, d, is initially five less than twice the number of cats, c</em>
D + 5 = 2C
<em>If she decides to add three more of each, the ratio of cats to dogs will be</em>
D + 8 = 2C + 3
<em>Could Bea's Pet Shop initially have 15 cats and 20 dogs?</em>
Simply plug in the numbers
20 + 5 = 2(15)
This is clearly not true: 25 does not equal 30
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She can spend a little over 30 dollars each day, ($30.35)
The answer is C but not sure about it please double check it
Thank you
I hope it’s help you
If the adjusted ratio was 2:7, then
2x is the number of pull-ups
and
7x is the number of box jumps.
You can state that since he completed 63 box jumps at the end of his training, then
7x=63,
x=9
and
2x=18.
The total number of exercises performed is 2x+9x=18+63=81.
As at start the ratio was 5:4, then
5y was the number of pull-ups
and
4y was the number of box jumps.
Therefore, 5y+4y=81,
9y=81,
y=9
and 5y=45, 4y=36.
Answer: Initially: 45 pull-ups and 36 box jumps. At the end: 18 pull-ups and 63 box jumps.
