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Korvikt [17]
2 years ago
14

A stick of butter in the shape of a rectangular prism has a length of 8 inches, a width of 3 inches, and a height of 3 inches. W

hat is the volume of the stick of butter?
Mathematics
1 answer:
SVEN [57.7K]2 years ago
5 0

Answer:

72in^3

Step-by-step explanation:

the information we know about the shape of the stick of butter:  

length = 8in

width = 3in

height=3in

The formula for the volume of a rectangular prism is:

volume=length*width*height

we find the volume by multiplying ll the measurements of the stick.

So we substitute the values to find the volume and we get the following:

volume=8in*3in*3in\\volume=72in^3

the volume of the stick of butter is 72in^3

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<span>(1/2)n = 0.015625 
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2 years ago
by visual inspection, determine the best-fitting regression model for the data plot below. A. No pattern B. Quadratic C.Linear D
liq [111]

Answer:

C) Linear

Step-by-step explanation:

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2 years ago
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Each day, X arrives at point A between 8:00 and 9:00 a.m., his times of arrival being uniformly distributed. Y arrives independe
astraxan [27]

Answer:

Y will arrive earlier than X one fourth of times.

Step-by-step explanation:

To solve this, we might notice that given that both events are independent of each other, the joint probability density function is the product of X and Y's probability density functions. For an uniformly distributed density function, we have that:

f_X(x) = \frac{1}{L}

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Now, as  X is distributed over a 1 hour interval, and Y is distributed over a 0.5 hour interval, we have:

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Now, the probability of an event is equal to the integral of the density probability function:

\iint_A f_{X,Y} (x,y) dx\, dy

Where A is the in which the event happens, in this case, the region in which Y<X (Y arrives before X)

It's useful to draw a diagram here, I have attached one in which you can see the integration region.

You can see there a box, that represents all possible outcomes for Y and X. There's a diagonal coming from the box's upper right corner, that diagonal represents the cases in which both X and Y arrive at the same time, under that line we have that Y arrives before X, that is our integration region.

Let's set up the integration:

\iint_A f_{X,Y} (x,y) dx\, dy\\\\\iint_A f_{X} (x) \, f_{Y} (y) dx\, dy\\\\2 \iint_A  dx\, dy

We have used here both the independence of the events and the uniformity of distributions, we take the 2 out because it's just a constant and now we just need to integrate. But the function we are integrating is just a 1! So we can take the integral as just the area of the integration region. From the diagram we can see that the region is a triangle of height 0.5 and base 0.5. thus the integral becomes:

2 \iint_A  dx\, dy= 2 \times \frac{0.5 \times 0.5 }{2} \\\\2 \iint_A  dx\, dy= \frac{1}{4}

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6 0
2 years ago
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Vitek1552 [10]
<h2>Answer with explanation:</h2>

To write an inequality and show on a number line all numbers: greater than (−3) but less than or equal to 3

Let n be the number, then -3 < n ≤3 .

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To the required inequality that shows all the numbers greater than (−3) but less than or equal to 3 : -3 < n ≤3 and the number line is represented below.

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AVprozaik [17]
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5 0
2 years ago
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