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Tanzania [10]
2 years ago
14

The angle of elevation to the top of a 20-story skyscraper is measured to be 2 degrees from a point on the ground 5,280 feet fro

m the building. What is the height of the skyscraper to the nearest hundredth foot?

Mathematics
2 answers:
spin [16.1K]2 years ago
7 0
<span>Height of the skyscraper to the nearest hundredth foot
= 5280 Tan(2)
= </span>184.38
Vlad1618 [11]2 years ago
3 0

Answer:

184.38\ ft

Step-by-step explanation:

we know that

In a right triangle the tangent function of an angle \theta is equal to divide the opposite side to the angle \theta by the adjacent side to the angle \theta

In this problem we have

\theta=2\°

adjacent\ side=5,280\ ft

Let

h-----> the opposite side to the angle \theta (represent the height)

so

tan(2\°)=h/5,280

h=5,280*tan(2\°)=184.38\ ft

see the attached figure to better understand the problem

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Which sequence of transformations confirms congruence by mapping shape I onto shape II?
Lubov Fominskaja [6]

Answer:

  • Neither of the choices is correct.

Explanation:

<u>1. Coordinates of the vertices of the figure I (preimage):</u>

  • (10, - 5)
  • (15, -5)
  • (10, - 10)
  • (15, -10)

<u />

<u>2. Coordinates of the vertices of the figure II (image):</u>

  • (0,10)
  • (0,15)
  • (-5,10)
  • (-5, 15)

Since many different rigid transformations can map the figure I into the figue II, you will need to use trial and error.

The most important is to do it in an educated way.

I will start by eliminating some options.

The first option, a reflection across the x-axis and 15 units left, does not work, because the reflection across the x-axis would shift the figure to a lower position than what you need.

The third option, a 90º counterclokwise rotation about the origin then a translation 10 units up, would move the figure to the second quadrant, and we need it in the third quadrant.

I will try now with the second choice, a 90º clockwise rotation and then 25 units up:

First, a 90º clockwise rotation, which is the same that a 270º counterclockwise rotation, follows the rule (x, y) → (y, -x)

Then, that results in:

  • (10, - 5) → (-5, -10)
  • (15, -5) → (-5, -15)
  • (10, - 10) → (-10, -10)
  • (15, -10) → (-10, -15)

Now, you can see that shifting 25 units up will not work, because you need that two x-coordinates become 0 (zero). So, this is not the correct set of transformations either.

A 180º rotation about the origin and a translation 10 units right follow this chain of rules:

  • (x, y) → (-x, -y) → (-x + 10, -y)

That means:

  • (10, - 5) → (-10,5) → (-10 + 10, 5) = (0, 5)
  • (15, -5) → (-15, 5) → (-15 + 10, 5) = (-5, 5)
  • (10, - 10) → (-10, 10) → (-10 + 10, 10) = (0, 10)
  • (15, -10) → (-15, 10) → (-15 + 10, 10) = (-5, 10)

        These last points do not coincide either with the vertices of the figure II.

In conclusion, neither of the choices gives the correct answer to the question.

8 0
2 years ago
Read 2 more answers
In JKL, mJ = 90, mK = 30, and mL = 60. Which of the following statements about JKL are true?
kumpel [21]

The <em><u>correct answers</u></em> are:

KL = 2*JL; JK = (√3)JL; and JK = ((√3)/2)KL

Explanation:

This is a 30-60-90 right triangle.  This type of triangle has a special relationship among the sides.  Let the smallest side, across from the 30° angle, be t.  This means JL = t.

The hypotenuse of the triangle is two times the length of the smallest side; this means that KL = 2t, which means that KL = 2*JL.

The side of the triangle opposite the 60° angle will be the "medium sized" side; it is equal to √3 times the smallest side, or √3t; this gives us that JK = √3t = (√3)JL.

Comparing JK to KL, we have

\frac{t\sqrt{3}}{2t}

The t on top and bottom cancel out, leaving us with the ratio (√3)/2.  This means that JK = ((√3)/2)KL.

8 0
2 years ago
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grin007 [14]

Answer:

Alexia completed 8 math problems and 9 science problems

Step-by-step explanation:

3 minutes per math problem (8*3) is 24

4 minutes per science problem (9*4) is 36

36+24=60 minutes

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2 years ago
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L
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Answer:

the answer is $5,000

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the question is asking what the initial value of the painting is and in the equation, they are trying to find out how much the painting will cost after t years. the 1.098 is how much the painting decreases each year and it is being multiplied by &5000 so $5000 is the original value of the painting.

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2 years ago
The perimeter of the school crossing sign is 102 inches what is the length of each side
Afina-wow [57]
The perimeter of the school crossing sign is 102 inches
length of each side = ?
in the question number of sides is not mentioned, so the answer may vary for the length of each side. if there is 5 sides divide 102 by 5, we get 20.4 answer so in case of 5 sides length of each side is 20.4 inches. if there is 4 sides divide 102 by 4 and we get 25.5 inches answer for the legnth each side.
6 0
2 years ago
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