John's average for making free throws in a basketball game is .80. In a one-and-one free throw situation (where he shoots a seco
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Answer : y>0
f(x) = 9*2^x
f(x) is an exponential function
When we plug in positive value for x , the value of y is positive
When we plug in negative value for x , the value y is also positive
So for any value of x, the y value is positive always.
Range is the set of y values for which the function is defined
y values are positive , so range is y >0
Answer:
a) the length of the wire for the circle =
b)the length of the wire for the square =
c) the smallest possible area = 126.02 in² into two decimal places
Step-by-step explanation:
If one piece of wire for the square is y; and another piece of wire for circle is (60-y).
Then; we can say; let the side of the square be b
so 4(b)=y
b=
Area of the square which is L² can now be said to be;
On the otherhand; let the radius (r) of the circle be;
2πr = 60-y
Area of the circle which is πr² can now be;
Total Area (A);
A =
=
For the smallest possible area;
∴
If we divide through with (2) and each entity move to the opposite side; we have:
By cross multiplying; we have:
2πy = 480 - 8y
collect like terms
(2π + 8) y = 480
which can be reduced to (π + 4)y = 240 by dividing through with 2
∴ since , we can determine for the length of the circle ;
60-y can now be;
=
=
=
=
also, the length of wire for the square (y) ;
The smallest possible area (A) =
= 126.0223095 in²
≅ 126.02 in² ( to two decimal places)
Circumcenter and circumcirle are shown in the attachment. Assume that the triangle is DEF instead of ABC and that the intersection of perpendiculars is H.
The definition of the circumcenter of a triangle is defined as the point of intersection of all the perpendicular bisectors in the triangle.
The circumcircle passes by all three of the triangle's vertices.
Based on the above, the right choiceS will be:
Point H is the center of the circle that passes through points D, E, and F.
HD = HE
The definition of the circumcenter of a triangle is defined as the point of intersection of all the perpendicular bisectors in the triangle.
The circumcircle passes by all three of the triangle's vertices.
Based on the above, the right choiceS will be:
Point H is the center of the circle that passes through points D, E, and F.
HD = HE