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Andrej [43]
2 years ago
11

How many molecules are in 1.35 moles of lactic acid (C6H6O)

Chemistry
1 answer:
Shkiper50 [21]2 years ago
6 0

Answer:

= 8.13 x 10²³ molecules of lactic acid per mole

Explanation:

Molecules of Lactic Acid in 1 mole:

One mole ( 1 mole) of any substance whether element or compound contains 6.02 x 10²³ particles of that substance.

That is => 1 mole substance = 6.02 x 10²³ particles of that substance

∴ 1.35 moles lactic acid = 1.35 moles x 6.02 x 10²³ particles lactic acid /mole

= 8.13 x 10²³ molecules of lactic acid per mole.

Note (for what it's worth) ... Number of Atoms ...

Given the formula of lactic acid C₆H₆O represents 1 mole of the compound, the <em><u>subscripts represent moles of each element </u></em>in the compound. That is, there are 6 moles carbon, 6 moles hydrogen and 1 mole oxygen atoms in each mole of lactic acid. So, if one were to ask, How many atoms of carbon are there in 1 mole of lactic acid? =>  then ...

1 mole C₆H₆O => 6 moles H = 6 moles H x 6.02 x 10²³ atoms/mole = 3.612 x 10²⁴ atoms of hydrogen in 1 mole of lactic acid. Same logic will give atoms of Hydrogen and Oxygen if needed.

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Your little sister asks you a scientific question: "Does chocolate milk come from brown cows?" In order to answer the question,
aksik [14]

Answer:

Hey there,

Your answer is iii. Brown cows produce white milk. (1 point) <u>and</u> ii. Brown cows never produce chocolate milk. (1 point)

You already know from the basic understanding that chocolate comes from beans, not cows, and is added to milk, and thereby- brown cows do not produce chocolate milk. You also know that they produce white milk.

Wbob1314

if you have any questions I <em><u>INSIST</u></em> you ask them in the comments.

5 0
2 years ago
A chemist is working on a reaction represented by this chemical equation:
erastova [34]

Answer is: A. 1.81 mol.

Balanced chemical reaction: FeCl₂ + 2KOH → Fe(OH)₂ + 2KCl.

n(FeCl₂) = 4.15 mol; amount of iron(II) chloride.

n(KOH) = 3.62 mol; amount of potassium hydroxide, limiting reactant.

From chemical reaction: n(KOH) : n(Fe(OH)₂) = 2 : 1.

n(Fe(OH)₂) = n(KOH) ÷ 2.

n(Fe(OH)₂) = 3.62 mol ÷ 2.

n(Fe(OH)₂) = 1.81 mol; amount of iron(II) hydroxide.

6 0
2 years ago
Read 2 more answers
495 cm3 of oxygen gas and 877 cm3 of nitrogen gas, both at 25.0 C and 114.7 kpa, are injected into an evacuated 536 cm3 flask. F
I am Lyosha [343]

Answer:

<u><em>Total pressure of the flask is 2.8999 atm.</em></u>

Explanation:

Given data:

Volume of oxygen (O2) gas= 495 cm3

                                              = 0.495 L (1 cm³ = 1 mL = 0.001 L)                                            

Volume of nitrogen (N2) gas =  877 cm3

                                               = 0.877 L (1 cm³ = 1 mL = 0.001 L)

volume of falsk = 536 cm3

                         = 0.536 L (1 cm³ = 1 mL = 0.001 L)

Temperature =  25 °C

T = (25°C + 273.15) K

    = 298.15 K

Pressure = 114.7 kPa

               = 114.700 Pa

Pressure (torr) = 114,700 / 101325

                        = 1.132 atm

Formula:

PV=nRT  <em>(ideal gas equation)</em>

P = pressure

V = volume

R (gas constnt)=  0.0821 L.atm/K.mol

T = temperature

n = number of moles for both gases

Solution:

Firstly we will find the number of moles for oxygen and nitrogen gas.

<u>For Oxygen:</u>

n = PV / RT

n = 1.132 atm × 0.495 L / 0.0821 L.atm/K.mol × 298.15 K

  = 0.560 / 24.47

  = 0.0229 moles

<u>For Nitrogen:</u>

n = PV / RT

n = 1.132 atm × 0.877 / 0.0821 L.atm/K.mol × 298.15 K

n = 0.992 / 24.47

  = 0.0406

Total moles = moles for oxygen gas + moles for nitrogen gas

  = 0.0229 moles + 0.0406 moles

n  = 0.0635 moles

Now put the values in formula

PV=nRT

P = nRT / V

P = 0.0635 × 0.0821 L.atm/K.mol × 298.15 K  /  0.536 L

P = 1.554 / 0.536

<u><em>P = 2.8999 atm</em></u>

Total pressure in the flask is  2.8999 atm, while assuming the temperature constant.

7 0
2 years ago
Read 2 more answers
Which mass of gas would occupy a volume of 3dm3 at 25°C and 1 atmosphere pressure?
balu736 [363]

Answer:

C 8.09 SO2 gas

Explanation:

As we have the volume (3dm³ = 3L), temperature (25°C + 273 = 298K), and pressure (1atm), we can solve to moles of gas using:

PV = nRT

PV / RT = n

1atm*3L / 0.082atmL/molK*298K =¨

0.123 moles of gas you have.

Now, to convert these moles to mass we use molar mass (32g/mol for O2, 28g/mol for N2, 64g/mol for SO2, and 44g/mol for CO2).

Mass of 0.123 moles of these gases is:

O2 = 0.123 moles * 32g/mol = 3.94g of O2. A is wrong

N2 = 0.123 moles * 28g/mol = 3.4g of N2. B is wrong

SO2 = 0.123 moles * 64.1g/mol = 7.9g of SO2≈ 8.09g of SO2, C is possible

CO2 = 0.123 moles * 44g/mol = 5.4g of CO2. D is wrong

Right answer is:

<h3>C 8.09 SO2 gas </h3>

8 0
2 years ago
The volume of a gas is 7.15 l measured at 1.00 atm. what is the pressure of the gas in mmhg if the volume is changed to 9.25 l?
IRINA_888 [86]
1 atm=7.15/9.25
Volume increase comes from reduced pressure
3 0
2 years ago
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