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a_sh-v [17]
2 years ago
12

A westbound section of freeway currently has three 12-ft wide lanes, a 6-ft right shoulder, and no ramps within 3 miles upstream

and downstream of the segment midpoint. It is on rolling terrain with 10% heavy vehicles and is operating at capacity with a peak-hour factor of 0.900. If the road is expanded to four 11-ft lanes with a 2-ft right shoulder, and traffic after the expansion is projected to increase by 10% with the same heavy vehicle percentage and peak hour factor, what is the new LOS and estimated density?
Engineering
1 answer:
iogann1982 [59]2 years ago
6 0

Answer:

The level of the service is loss and the density is 34.2248 pc/mi/ln

Explanation:

the solution is attached in the Word file

Download docx
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Consider the following class definitions: class smart class superSmart: public smart { { public: public: void print() const; voi
arsen [322]

Answer:

a) There is no any private member of smart which are public members of superSmart.

Explanation:

5 0
2 years ago
Write a program with total change amount as an integer input, and output the change using the fewest coins, one coin type per li
pshichka [43]

Answer:

The C code is given below with appropriate comments

Explanation:

#include<stdio.h>

//defining constants

#define DOLLAR 100

#define QUARTER 25

#define DIME 10

#define NICKEL 5

#define PENNIES 1

//converting method

void ExactChange(int userTotal,int coinVals[])

{

//checking dollars

if (userTotal >=100)

{

coinVals[0]=userTotal/DOLLAR;

userTotal=userTotal-(100*coinVals[0]);

}

//checking quarters

if (userTotal >=25)

{

coinVals[1]=userTotal/QUARTER;

userTotal=userTotal-(25*coinVals[1] );

}

//checking dimes

if (userTotal >=10)

{

coinVals[2]=userTotal/DIME;

userTotal=userTotal-(10*coinVals[2]);

}

//checking nickels

if (userTotal >=5)

{

coinVals[3]=userTotal/NICKEL;

userTotal=userTotal-(5*coinVals[3]);

}

//checking pennies

if (userTotal >=1)

{

coinVals[4]=userTotal/PENNIES;

userTotal=userTotal-coinVals[4];

}

}

//main method

int main() {

//defining the variables

int amount;

//asking for input

printf("Enter the amount in cents :");

//reading the input

scanf("%d",&amount);

//validating the input

if(amount<1)

{

//printing the message

printf("No change..!");

}

//when the input is >0

else

{

int coinVals[5]={0,0,0,0,0};

ExactChange(amount,coinVals);

//checking dollars

if (coinVals[0]>0)

{

//printing dollars

printf("%d Dollar",coinVals[0]);

if(coinVals[0]>1) printf("s");

}

//checking quarters

if (coinVals[1]>0)

{

//printing quarters

printf(" %d Quarter",coinVals[1]);

if(coinVals[1]>1) printf("s");

}

//checking dimes

if (coinVals[2]>0)

{

//printing dimes

printf(" %d Dime",coinVals[2]);

if(coinVals[2]>1) printf("s");

}

//checking nickels

if (coinVals[3]>0)

{

//prinitng nickels

printf(" %d Nickel",coinVals[3]);

if(coinVals[3]>1) printf("s");

}

//checking pennies

if (coinVals[4]>0)

{

//printing pennies

printf(" %d Penn",coinVals[4]);

if(coinVals[4]>1) printf("ies");

else printf("y");

}

}

//end of main method

}

6 0
2 years ago
You want to determine whether the race of the defendant has an impact on jury verdicts. You assign participants to watch a trial
Andru [333]

Answer:

The confidence scale represents an ordinal scale of measurement

Explanation:

An ordinal scale or level of measurement is used to measure attributes that can be ranked or ordered, but the interval between the attributes do not have quantitative significance. In this case, the measurement was done on a scale of 1 - 7, with a "1" being; not all that race of defendant has an impact on jury verdicts and a "7" being "very" meaning that race indeed has impact on jury verdicts. Another example can be a survey carried out on the level of customer satisfaction on a particular product, with "1" most dissatisfied and "10 " representing most satisfied. In the first example, it is wrong to say that the difference between 1 being "not at all" and maybe 3 is the same as the difference between 5 and 7 which have different connotations, because the numbers are merely for tagging and not to quantify.

Other levels of measurement include:

1. Nominal: this is the simplest level of measurement and it is simply used to categorize the attributes. Example is taking a survey on gender in the categories of male, female and transgender.

2. Interval: the interval scale is used when the distance between two attributes have meanings but there is no true zero value associated with the scale.

3. Ratio: this combines all the other three levels of measurement and is used to categorize, used to show ranking, has meaningful distances between the attributes and the scale has a true zero point. Example is the measurement of temperature using the celcius scale thermometer, where there is a true zero point at 0°C and the distance between 5°C and 10°C is the same as the distance between 10°C and 15°C.

6 0
2 years ago
A pair of spur gears with 20 degree pressure angle, full-depth, involute teeth transmits 65 hp. The pinion is mounted on a shaft
vfiekz [6]

Answer:

See explaination

Explanation:

a) The pitch circle diameter of pinion in inches is given by

Dp=Np/P

Where

Np= No. of teeth in pinion = 26

P =diametral pitch= 6

Hence

Dp= 26/6 = 4.333 in

Pinion angular speed\omega _{p} =1250 rpm = 130.9 rad/s

Therefore pitch line speed

V=Dp/2\omega _{p} = 4.333/2x130.9

= 283.62 in/s

V= 23.63 ft/s

V=1418 ft/min

b) The pitch circle diameter og gear is given by

Dg= Ng/P= 48/6 = 8 in

The center distance is given by

C=(Dp+Dg)/2

= (4.333+8)/2

C= 6.167 in

c) The torque on the pinion is given by

Tp= P/\omega _{p}

Where

P = transmitted power, =65 hp = 65x550= 35750 lt-lb/s

Tp= 35750/130.9

= 273.1 ft-lb

d) Speed ratio is given as

R=Ng/Np= 48/26 = 1.8461

Hence speed of gear is

\omega _{g}=\frac{\omega _{p}}{R}

= 130.9/1.8461

= 70.9 rad/s

Therefore torque on gear is given as

Tg= P/\omega _{g} = 35750/70.9

= 504.2 ft-lb

e) Assuming transmission eficiency of 100%

Output hp=input hp= 65 hp

f) Tangential force on gear teeth is given by

Fgt= Tg/(Dg/2)

= 504.2x2/8

= 126.05 lb

g) Radial force on ger teeth is given as

Fgr= Fgt tan\phi

Where

\phi is pressure angle = 200

Hence

Fgr= 126.05tan200

= 45.88 lb

h) The normal force on gear teeth is given as

F=Fgt/cos\phi

= 126.05/cos200

= 134.14 lb

4 0
2 years ago
If a server takes precisely 15 seconds to serve a customer and customers arrive exactly every 20 seconds, what is the average wa
labwork [276]
The average waiting time is 10 seconds
7 0
2 years ago
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