Air traffic controller Seymour Plains must quickly calculate the altitude of an incoming jet. He records the jet’s angle of elev
ation as 8°. The jet signals that its land (horizontal) distance from the control tower is 74 km. Calculate the altitude of the jet to the nearest meter
1 answer:
Answer:
Altitude of the jet is 10.40km
Step-by-step explanation:
The angle of elevation = 8°
Horizontal distance (adjacent to the angle) = 74km
Altitude of the plane (opposite) = ?
Kindly check attached document for better illustration.
To solve this question, we have to use tangent rule since we have adjacent and angle, but no opposite.
Tanθ = opposite / adjacent
θ = 8°
Adjacent = 74km
Opposite = ?
Tan 8 = x / 74
Opposite = 74 * tan8
Opposite = 10.40
The altitude of the jet is 10.40km
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Refer to the diagram shown below.
Let x = m∠ADB.
Because m∠BDC is 32° greater than m∠ADB, therefore
m∠BDC = x + 32°
Each angle of a rectangle is 90°, therefore
x + (x+32) = 90
2x + 32 = 90
2x = 58
x = 29°
x+32 = 61°
Answer:
m∠BDC = 61°
m∠ADB = 29°
Let x = m∠ADB.
Because m∠BDC is 32° greater than m∠ADB, therefore
m∠BDC = x + 32°
Each angle of a rectangle is 90°, therefore
x + (x+32) = 90
2x + 32 = 90
2x = 58
x = 29°
x+32 = 61°
Answer:
m∠BDC = 61°
m∠ADB = 29°