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siniylev [52]
2 years ago
10

In a laboratory experiment, C. elegans and B. thuringiensis were cultured individually (control) or together (experimental) for

150 days. Under optimal conditions, the generation time of C. elegans is approximately 3.5 days and the generation time of B. thuringiensis is approximately 25 minutes. At the end of the experiment, the change in virulence of B. thuringiensis and the change in resistance of C. elegans to BT toxin were determined. (a) Calculate the maximum number of generations that is possible in individual cultures of C. elegans AND the maximum number of generations that is possible in individual cultures of B. thuringiensis in 150 days.
Biology
1 answer:
serious [3.7K]2 years ago
3 0

Answer:

Explanation:

If the investigator wishes to watch the movement of C. Elegans (a roundworm), then he should be using compound microscopes. These microscopes are light illuminates and image that can be perceived is a two dimensional. Using this would allow you to magnify to a certain level so you can view individual cells and even cells that are living and moving. Typically compound microscopes can magnify up to 1000 times magnification. It has two convex lenses which has short focal lengths to allow a much higher level of magnification as compared to a simple microscope. These lenses are called the ocular lens and the objective lens.

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Convert enzyme concentrations of 2.5%, 5.0%, and 10% to ppt units.
slavikrds [6]

Answer:

2.5 x 10¹⁰ ppt

5.0 x 10¹⁰ ppt

1.0 x 10¹¹ ppt

Explanation:

The notation ppt refers to parts per trillion units, that is, how many parts of enzyme are there in 1 trillion parts. Percentage refers to the number of parts per 100 units. Converting the given values from percentage to ppt:

\frac{2.5}{100}=\frac{a}{1,000,000,000,000}\\a=2.5 *10^{10}\ ppt\\\\\frac{5.0}{100}=\frac{b}{1,000,000,000,000}\\b=5.0 *10^{10}\ ppt\\\\\frac{10}{100}=\frac{c}{1,000,000,000,000}\\c=1*10^{11}\ ppt

The concentration in ppt are:

2.5 x 10¹⁰ ppt

5.0 x 10¹⁰ ppt

1.0 x 10¹¹ ppt

7 0
2 years ago
Suppose two populations of Anolis lizards are of equal size at the beginning of an experiment. One population (the experimental
Olin [163]

Answer:

Per capita interaction strength is -0.046875.

Explanation:

N=50, D=200, Y=16, interaction strength is  estimated as (N-D)/(DY)

(50-200)/(200*16)= -0.046875

3 0
2 years ago
If the nucleotide or base sequence of the dna strand used as a template for messenger rna synthesis is acgtt, then what would be
KATRIN_1 [288]
It is simply the complementary bases to that sequence but change the thymine to Uracil because it is RNA not DNA.
5 0
2 years ago
The heterotroph hypothesis of the origin of life states that basic organic building blocks formed from inorganic molecules under
azamat

Answer:

1) abiotic synthesis of small organic molecules (monomers)

2) joining of monomers into polymers

3) packaging of these molecules into protobionts, droplets with membranes that maintained a distinct internal chemistry

4) origin of self-replicating molecules that eventually made inheritance possible

Explanation:

8 0
2 years ago
The diagram is a representation of part of a plant cell. Identify the locations where proton concentration builds up during phot
oksian1 [2.3K]

The process of cellular respiration is achieved in plants by the process of photosynthesis. The energy from glucose is derived in this process. The steps of the cellular respiration includes the glycolysis, the kreb's cycle, and the oxidative phosphorylation. During this process, the proton concentration builds in the thylakoid space of the plant cell.

8 0
2 years ago
Read 2 more answers
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