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mafiozo [28]
2 years ago
13

A rectifier charges a battery bank in a substation. The bank rated dc voltage is 48 V. The required charging current is 25 A. Th

e available ac supply is 120 V. The internal resistance of the battery is 2.5 Ω. (a) Analyze the operating conditions of the charger. Plot the ac and dc voltage and current, and determine the feasibility of delay angle control. (b) Calculate the delay angle needed to maintain the 25 A charging current. (c) Calculate the power and power factor at the ac side.

Engineering
1 answer:
Vsevolod [243]2 years ago
7 0

Answer:

See explaination

Explanation:

A constant voltage source is called a DC Voltage with a voltage that varies periodically with time is called an AC voltage. Voltage is measured in volts, with one volt being defined as the electrical pressure required to force an electrical current of one ampere through a resistance of one Ohm.

Please check the attached file.

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Two resistors of values 7.0 and 15.0 Ω are connected in parallel. This combination in turn is hooked in series with a 3.8- Ω res
Alex

Answer:

1.8A

Explanation:

Firstly, we need to find the effective resistance in the circuit.

For the two parallel resistors, the effective resistance is;

1/R = 1/7 + 1/15

R = 8.57Ω

Now let's connect it in series with the series resistor

R = 8.57 + 3.8 = 12.37Ω

This is the total effective resistance

The total current is therefore

22.3/8.57 = 1.8A

This is also the current flowing through the 3.8 resistor since it is connected in series

7 0
2 years ago
Lydia is the CEO for a large pharmaceutical manufacturer. Her company is in the final stages of FDA
weqwewe [10]
OSHA inspections are generally unannounced. In fact, except in four exceptional circumstances when advance notice may be given.


It is a criminal offense for any person to give unauthorized advance notice of an OSHA inspection.
5 0
2 years ago
Evan notices a small fire in his workplace. Since the fire is small and the atmosphere is not smoky he decides to fight the fire
Norma-Jean [14]

Answer:

not calling the firemean

Explanation:

7 0
2 years ago
When should you exercise extreme caution around power lines?
Elis [28]

<em>You should take note and exercise extreme precautions when you are near power lines and consider the following: </em>

<em> </em>

<em>1. Make sure that you have a good distance away from the lines. The minimum distance you can get is 10 feet away from the lines. Be cautious as well when you see broken lines as they could still harm you and electrified you. </em>

<em>2. Do not make ladders, equipments and things around you touch the power lines as it may harm you as well. </em>

<em>3. Clear everything and ensure that no things are near you before you lift your hands and other tools.</em>

6 0
2 years ago
An electric field is expressed in rectangular coordinates by E = 6x2ax + 6y ay +4az V/m.Find:a) VMN if point M and N are specifi
Fittoniya [83]

Answer:

a.) -147V

b.) -120V

c.) 51V

Explanation:

a.) Equation for potential difference is the integral of the electrical field from a to b for the voltage V_ba = V(b)-V(a).

b.) The problem becomes easier to solve if you draw out the circuit. Since potential at Q is 0, then Q is at ground. So voltage across V_MQ is the same as potential at V_M.

c.) Same process as part b. Draw out the circuit and you'll see that the potential a point V_N is the same as the voltage across V_NP added with the 2V from the other box.

Honestly, these things take practice to get used to. It's really hard to explain this.

3 0
2 years ago
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