Step-by-step explanation:
Start by writing 492,623 in standard form
4 hundred thousands + 9 ten thousands + 2 thousands + 6 hundreds + 2 tens + 3 ones
We can write this in other ways by moving a digit to the next smaller place value. For example, we move the 4 one place to the right to get 49 ten thousands:
49 ten thousands + 2 thousands + 6 hundreds + 2 tens + 3 ones
Then, we can move the 49 ten thousands to the right to get 492 thousands, and we can move 6 hundreds to the right to get 62 tens.
492 thousands + 62 tens + 3 ones
Or, we can do this:
4926 hundreds + 23 ones
he payed 3,000 in hand payment then gave checks per...mnth for 6 years to equal the needed amount
Parameterize the intersection by setting
, so that
The length of the path
is then given by the line integral along
,
where
. We have
and so the line integral is
This result is fortuitous, since we can write
and so the integral reduces to
Well since the pattern is odd, even, odd, even you are just as likley to pull on odd (<span>not evenly divisible by 2) numebr as an even number, so the option is C.
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Answer:
The distance at which the timekeeper is the race car at the start is 50 feet.
Step-by-step explanation:
You know that the car's distance from the timekeeper is represented by
y=293*x +50
where x is time in seconds and y is distance in feet from the timekeeper's position.
You want to determine how far the timekeeper is from the race car at the start. That is, the distance the timekeeper is from the car when the time is equal to zero. This indicates that x = 0. Replacing x by that value in the expression of the distance of the car from the timekeeper as a function of time and solving:
y=293*0 +50
you get:
y=50
<u><em>The distance at which the timekeeper is the race car at the start is 50 feet.</em></u>
