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34kurt
2 years ago
8

A boat is approaching a cliff known to be 40m tall. The angle of elevation is 30°. How far away is the boat from the cliff?

Mathematics
1 answer:
allochka39001 [22]2 years ago
5 0

Answer:

x = 40 * \sqrt{3}  meters

Step-by-step explanation:

You have a 30-60-90 right triangle in this situation.

the height of this triangle is 40 meters

the opposite angle is 30 degrees.

use the tangent.

let x = distance between boat and cliff

tan 30 = 40/x

1/root (3) = 40/x

x = 40 * \sqrt{3}  meters

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Answer:

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Step-by-step explanation:

Since the length of day is L(t)=727+22sin[2π(t−80.75)/365], the maximum length of day is obtained when sin[2π(t−80.75)/365] is at its maximum value which is 1. So. sin[2π(t−80.75)/365] = 1

We now solve this to find the day at which this maximum value occurs.

sin[2π(t−80.75)/365] = 1

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1 year ago
What is the lateral area of a right rectangular prism that has rectangular bases measuring 3" by 5" and a height of 6"?
Mademuasel [1]

Answer:

The answer is the option A

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Step-by-step explanation:

we know that

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6 0
2 years ago
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Step-by-step explanation:

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Answer:

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