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OLEGan [10]
2 years ago
10

On a coordinate plane, a straight line with a negative slope, labeled f of x, crosses the y-axis at (0, 4), and the x-axis at (4

, 0). Which is true regarding the graphed function f(x)? f of 0 = 3 f of 5 = negative 1 f of 3 = 2 f of 2 = negative 2
Mathematics
2 answers:
Inga [223]2 years ago
5 0

Answer: 1 f of 3 = 2 f of 2 = negative

Step-by-step explanation:

alexandr1967 [171]2 years ago
5 0

Answer:

B

Step-by-step explanation:

I took the test

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Jabari owns 100 shares of Stock A and 45 shares of Stock B. For the past month, his stocks have been fluctuating inversely each
aniked [119]
This is how we solved and make the equation.
Stock A = 100
Stock B = 45

For the past months, his stocks inversely decreased.
Stock A = m cents / share
Stock B = n cents * share

So the equation is
= 100 (0.01m) + 45 (0.01n)
<span>= m + 0.45n</span>
6 0
2 years ago
Amir drove from Jerusalem down to the lowest place on Earth, the Dead Sea, descending at a rate of 12 meters per minute. He was
RUDIKE [14]

Answer:

Graph these two points: (0, 360), (30, 0)

Step-by-step explanation:

Since Amir drove for 30 minutes at a rate of 12 meters, that means that he started at an elevation of 360 feet. The easiest way to graph this, is to place one dot at (0, 360), and at (30, 0).

8 0
2 years ago
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It costs $23 per hour plus a flat fee of $16 for a plumber to make a house call. What is the equation of the form y = mx + b for
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D is the best choice because y would be the total amount of money he would have to pay. X would be the amount of hours he uses the phone and the hourly fee is 23 so it would be 23x. the flat fee was 16 so you just add that on to the hourly fee. The whole equation should be y = 23x + 16
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2 years ago
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Let e1= 1 0 and e2= 0 1 ​, y1= 4 5 ​, and y2= −2 7 ​, and let​ T: ℝ2→ℝ2 be a linear transformation that maps e1 into y1 and maps
Furkat [3]

Answer:

The image of \left[\begin{array}{c}4&-4\end{array}\right] through T is \left[\begin{array}{c}24&-8\end{array}\right]

Step-by-step explanation:

We know that T: IR^{2}  → IR^{2} is a linear transformation that maps e_{1} into y_{1} ⇒

T(e_{1})=y_{1}

And also maps e_{2} into y_{2}  ⇒

T(e_{2})=y_{2}

We need to find the image of the vector \left[\begin{array}{c}4&-4\end{array}\right]

We know that exists a matrix A from IR^{2x2} (because of how T was defined) such that :

T(x)=Ax for all x ∈ IR^{2}

We can find the matrix A by applying T to a base of the domain (IR^{2}).

Notice that we have that data :

B_{IR^{2}}= {e_{1},e_{2}}

Being B_{IR^{2}} the cannonic base of IR^{2}

The following step is to put the images from the vectors of the base into the columns of the new matrix A :

T(\left[\begin{array}{c}1&0\end{array}\right])=\left[\begin{array}{c}4&5\end{array}\right]   (Data of the problem)

T(\left[\begin{array}{c}0&1\end{array}\right])=\left[\begin{array}{c}-2&7\end{array}\right]   (Data of the problem)

Writing the matrix A :

A=\left[\begin{array}{cc}4&-2\\5&7\\\end{array}\right]

Now with the matrix A we can find the image of \left[\begin{array}{c}4&-4\\\end{array}\right] such as :

T(x)=Ax ⇒

T(\left[\begin{array}{c}4&-4\end{array}\right])=\left[\begin{array}{cc}4&-2\\5&7\\\end{array}\right]\left[\begin{array}{c}4&-4\end{array}\right]=\left[\begin{array}{c}24&-8\end{array}\right]

We found out that the image of \left[\begin{array}{c}4&-4\end{array}\right] through T is the vector \left[\begin{array}{c}24&-8\end{array}\right]

3 0
2 years ago
Based on a​ poll, 67​% of Internet users are more careful about personal information when using a public​ Wi-Fi hotspot. What is
daser333 [38]

Answer:

The required probability is 0.988.

Step-by-step explanation:

Consider the provided information.

Based on a​ poll, 67​% of Internet users are more careful about personal information when using a public​ Wi-Fi hotspot.

That means the probability of more careful is 0.67

The probability of not careful is: 1-0.67 = 0.33

We have selected four random Internet​ users. we need to find the probability that at least one is more careful about personal information.

P(At least one careful) = 1 - P(None of them careful)

P(At least one careful) = 1 - (0.33×0.33×0.33×0.33)

P(At least one careful) = 1 - 0.012

P(At least one careful) = 0.988

Hence, the required probability is 0.988.

The result may be higher because of the convenience bias in retrieving the sample. Because the survey subjects volunteered to​ respond not random.

3 0
2 years ago
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