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OLEGan [10]
2 years ago
10

On a coordinate plane, a straight line with a negative slope, labeled f of x, crosses the y-axis at (0, 4), and the x-axis at (4

, 0). Which is true regarding the graphed function f(x)? f of 0 = 3 f of 5 = negative 1 f of 3 = 2 f of 2 = negative 2
Mathematics
2 answers:
Inga [223]2 years ago
5 0

Answer: 1 f of 3 = 2 f of 2 = negative

Step-by-step explanation:

alexandr1967 [171]2 years ago
5 0

Answer:

B

Step-by-step explanation:

I took the test

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AC CE and D is the midpoint of CE. IF CE 10x + 18, DE =7x -1, and BC = 9x - 2, find AB, AB =
Anastasy [175]

Answer:

<h3>      If you mean: AC=CE, the answer is:  AB = 24</h3>

Step-by-step explanation:

D is the midpoint of CE, then

CD = DE = 0.5CE = 0.5(10x+18) = 5x + 9

So:   5x + 9 = 7x - 1

            -9          -9

        5x  =  7x - 8

        -7x      -7x

       -2x  =  -8

      ÷(-2)       ÷(-2)        

          x  =  4

AC = CE = 10x + 18 = 40 + 18 = 58

BC = 9x - 2 = 36 - 2= 34

AB = AC - BC = 58 - 34 = 24

4 0
2 years ago
Can you answer this plzz and the pic that goes with it???????? Thx soo much!!!!!
kkurt [141]

Answer: c. t > 82

Step-by-step explanation:

Let t represent the number of tickets that the committee would sell.

The dance committee of Pine Bluff Middle School earns $72 from a bake sale and will earn $4 for each ticket they sell to the Spring Fling dance. This means that the revenue that they would generate from selling x tickets is

72 + 4x

The dance will cost $400.

To make profit, revenue must be greater than cost. Therefore, the inequality to determine the number of tickets the committee could sell to have money left over after they pay for this year's dance is

72 + 4x > 400

4x > 400 - 72

4x > 428

x > 328/4

x > 82

5 0
1 year ago
Read 2 more answers
On a test, leo is asked to completely factor the polynomial 3x3 – 3x 5x2 – 5. he uses double grouping to get (x2 – 1)(3x 5). has
Agata [3.3K]

No, Leo's answer is not a product of prime polynomials because x2 – 1 can be factored. This is a difference of squares. He should continue factoring to get

(x – 1)(x + 1)(3x + 5).

8 0
2 years ago
Read 2 more answers
Two professors are applying for grants. Professor Jane has a probability of 0.61 of being funded. Professor Joe has probability
Anna11 [10]

Answer:

  • a. 0.1647;
  • b. 0.7153;
  • c. 0.4453.

Step-by-step explanation:

By definition, if two event A and B are independent, then

P(A\cap B) = P(A) \cdot P(B). (P(A\cap B) is the probability that the outcome of both event A and event B are true.)

<h3>a.</h3>

Since the outcome of these two events are independent,

\begin{aligned}P(\texttt{Jane} \cap \texttt{Joe}) &= P(\texttt{Jane}) \cdot P(\texttt{Joe})\\ &= 0.61 \times 0.27 \\&= 0.1647\end{aligned}.

<h3>b.</h3>

The logic not operator \lnot or the prime superscript ^{\prime} denotes that an event does not happen.  

P(\texttt{Jane}^{\prime}) = 1 - P(\texttt{Jane}) = 1- 0.61 = 0.39.

P(\texttt{Joe}^{\prime}) = 1 - P(\texttt{Joe}) = 1- 0.27 = 0.73.

Since the two events \texttt{Jane} and \texttt{Joe}, \texttt{Jane}^{\prime} and \texttt{Joe}^{\prime} are also independent. Probability that neither professor got funded:

P(\texttt{Jane}^{\prime} \cap \texttt{Joe}^{\prime}) = P(\texttt{Jane}^{\prime}) \cdot P(\texttt{Joe}^{\prime}) = 0.39 \times 0.73 = 0.2847.

Probability that at least one professor got funded- in other words, it is not true that neither professor got funded:

P((\texttt{Jane}^{\prime} \cap \texttt{Joe}^{\prime})^{\prime}) = 1- P(\texttt{Jane}^{\prime} \cap \texttt{Joe}^{\prime}) = 0.7153.

<h3>c.</h3>

Similarly, since the two events \texttt{Jane} and \texttt{Joe}, \texttt{Jane} and \texttt{Joe}^{\prime} are also independent. Probability that Jane but not Joe got funded:

P(\texttt{Jane} \cap (\texttt{Joe}^{\prime})) = P(\texttt{Jane}) \cdot P(\texttt{Joe}^{\prime}) = 0.61 \times 0.73 = 0.4453.

4 0
1 year ago
Kim's business earns $10,000 per month. Kim's non-employee expenses are $3,000 per month. If Kim wants $2,000 in profit per mont
MA_775_DIABLO [31]

Answer:

Kim's business earns $10,000 per month.

Kim's non-employee expenses are $3,000 per month.

If Kim wants $2,000 in profit per month, then the maximum amount Kim can spend for employee:

10000 - 3000 - 2000 =5000

If each employee costs $1,000 per month, Kim can recruit 5000/1000 = 5 as the maximum number of employees.

Hope this helps

:)

8 0
1 year ago
Read 2 more answers
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